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solong [7]
2 years ago
6

Percent Composition and Determining Empirical And Molecular Formulas

Chemistry
1 answer:
raketka [301]2 years ago
3 0

Answer:

% comp. H = 2.8%, % comp. Cl = 97.2%

Explanation:

HCl mass = mass of H + mass of Cl

HCL mass = 1.00794 + 35.453 = 36.46094

% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)

% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)

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Mg(Oh)2 calculate molar mass
kvv77 [185]

Answer:

From molar mass=total RAM

Mg=24,O=16,H=1

24+(16+1)×2

Therefore Molar mass=58g/mol

4 0
3 years ago
Which of the following describes a situation where competition between producers exists
Oksanka [162]

Answer:

C. two or more producers are trying to sell the same good or service to the same consumers.

Explanation:

APEX

7 0
4 years ago
A polymer sample combines five different molecular-weight fractions, each of equal weight. The molecular weights of these fracti
kakasveta [241]

Answer:

Mn = 43,783

Mw = 60,000

Mz = 73,333

narrow distribution = 1.37

Explanation:

The molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000. This means their Mi is respectively: (The molar weight (Mi) of the fractions)

Fraction 1 : Mi = 20  *10^3

Fraction 2: Mi = 40 *10^3

Fraction 3 : Mi = 60 *10^3

Fraction 4: Mi = 80 *10^3

Fraction 5 : Mi = 100  *10^3

The ΣMi = 300*10^-3

The Wi (mass of the fractions is for all the fractions the same, let's say 1)

So Wi = 1+1+1+1+1 = 5

Since number of moles = mass / Molar mass

The number of moles is respectively: ni = Wi/Mi (x10^5)

Fraction 1 : ni = Wi/Mi = 1/20000 = 5

Fraction 2: ni = 1/40000 = 2.5

Fraction 3 : ni =1/60000 = 1.67

Fraction 4: ni = 1/80000 = 1.25

Fraction 5 : ni= 1/100000 = 1

The Σni = 11.42

Mn = ΣWi/ni = 5/11.42*10^-5 = 43,783

Mw = (ΣWi * Mi)/ΣWi  = 300,000 /5 = 60,000

Mz = (ΣWi * Mi²)/ΣWi *Mi = (4*10^8 +16*10^8 +36*10^8 +64*10^8 +100*10^8) /300,000  =73,333

Mz/Mn = narrow distribution =60,000/43,783 = 1.37

7 0
3 years ago
Read 2 more answers
Write the ionic charges (such as Ca2+) and chemical formulas and fill-in the table below.
Vikentia [17]

1) Lithium and fluorine:

Ionic charges: lithium cation Li⁺ and fluorine anion F⁻.

Chemical formula LiF.

In ionic salt lithium fluoride (LiF), fluorine has electronegativity approximately χ = 4 and lithium χ = 1 (Δχ = 4 - 1; Δχ = 3).

Fluorine attracts electron and it has negative charge and lithium has positive charge.

2) Beryllium and oxygen:

Ionic charges cation Be²⁺ and anion O²⁻.

Chemical formula is BeO.

Beryllium is metal from group 2 and oxygen is nonmetal from group 16.

Electron configuration of beryllium: ₄Be: 1s² 2s², it has two valence electrons in 2s orbital.

Beryllium lose two electrons and to gain electron configuration as noble gas helium (He).

Electron configuration of oxygen atom: ₈O 1s² 2s² 2p⁴.

Oxygen gain two valence electron to form anion with stable electron configuration as noble gas neon (atomic number 10).

3) Magnesium and fluorine:  

Ionic charges cation Mg²⁺ and anion F⁻.

Chemical formula is MgF₂.

Magnesium fluoride (MgF₂) is salt, ionic compound.  

Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).  

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.  

Fluorine (F) is nonmetal with greatest electronegativity, which means it easily gain electrons.  

Fluorine has atomic number 9, which means it has 9 protons and 9 electrons. It gain one electron to form fluorine anion (F⁻) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.  

4) Aluminum and chlorine:  

Ionic charges cation Al³⁺ and anion Cl⁻.

Chemical formula is AlCl₃.

The right name for AlCl₃ is aluminium chloride.

Aluminium chloride is a salt with ionic bonds.

Aluminium (metal from group 13) has oxidation number +3 and chlorine (nonmetal from group 17) has oxidation number -1, chemical compound has neutral charge (+3 + 3 · (-1) = 0).

5) Beryllium and nitrogen:  

Ionic charges cation Be²⁺ and anion N³⁻.

Chemical formula is Be₃N₂.

Atomic number of nitrogen is 7, it has 7 protons and 7 electrons.

Electron configuration of nitrogen atom: ₇N 1s² 2s² 2p³.

Nitrogen gain three electrons to form anion with stable electron configuration as noble gas neon (atomic number 10).

4 0
3 years ago
Three moles of an ideal gas undergo a reversible isothermal compression at temperature 18.0 ?c. during this compression, an amou
Lena [83]
We calculate the entropy of an ideal gas follows:

<span>For an isothermal compression, change in internal energy is equal to zero.</span>
<span>Thus, the heat added to the gas is equal to the work done on the gas which is given as 1750 J.</span>

<span>Entropy would be 1750/301 = 5.81 J/K </span>
3 0
3 years ago
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