Ethylene glycol reduces the cooling efficiency of water because it has a lower heat capacity as compared to water. A substance with low heat capacity would mean that the material only needs a small amount of energy to increase its temperature. So, for ethylene glycol, the heat transfer would be faster decreasing the cooling efficiency.
Answer:
4.9 N/m
Explanation:
m = 0.1 kg
x = 0.2 m
Let k be the spring constant.
As teh weight is balanced by the tension in the spring
Weight = force = mass x acceleration due to gravity
F = m x g = 0.1 x 9.8 = 0.98 N
This force si balanced by spring force
F = k x
Where, k be the spring constant and x be the displacement in spring
0.98 = k (0.2)
k = 4.9 N/m
Answer:
a) ![q=4.92*10^{-8} C](https://tex.z-dn.net/?f=q%3D4.92%2A10%5E%7B-8%7D%20C)
b) ![m=4.026*10^{-6} kg](https://tex.z-dn.net/?f=m%3D4.026%2A10%5E%7B-6%7D%20kg)
Explanation:
From the question we are told that:
Separation distance ![d=2.65*10^{-2} m](https://tex.z-dn.net/?f=d%3D2.65%2A10%5E%7B-2%7D%20m)
Acceleration 1 ![a_1=5.00*10^3 m/s^2,](https://tex.z-dn.net/?f=a_1%3D5.00%2A10%5E3%20m%2Fs%5E2%2C)
Acceleration 2 ![a_2=7.70*10^3 m/s^2,](https://tex.z-dn.net/?f=a_2%3D7.70%2A10%5E3%20m%2Fs%5E2%2C)
Mass 1 ![m_1=6.20*10^{-6}](https://tex.z-dn.net/?f=m_1%3D6.20%2A10%5E%7B-6%7D)
Generally the equation for Force is mathematically given by
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
For Particle 1
![F=6.2*10^{-6} *5*10^3](https://tex.z-dn.net/?f=F%3D6.2%2A10%5E%7B-6%7D%20%2A5%2A10%5E3)
![F=0.031 N](https://tex.z-dn.net/?f=F%3D0.031%20N)
Also
![F=\frac{kq_1*q2}{r^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_1%2Aq2%7D%7Br%5E2%7D)
Where
![q_1=q_2](https://tex.z-dn.net/?f=q_1%3Dq_2)
Therefore
![0.031=\frac{9*10^9*q^2}{(2.65*10^-2)^2}](https://tex.z-dn.net/?f=0.031%3D%5Cfrac%7B9%2A10%5E9%2Aq%5E2%7D%7B%282.65%2A10%5E-2%29%5E2%7D)
![q=4.92*10^{-8} C](https://tex.z-dn.net/?f=q%3D4.92%2A10%5E%7B-8%7D%20C)
b)
Generally the equation for Force is mathematically given by
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
![0.031=7.7*10^3](https://tex.z-dn.net/?f=0.031%3D7.7%2A10%5E3)
![m=4.026*10^{-6} kg](https://tex.z-dn.net/?f=m%3D4.026%2A10%5E%7B-6%7D%20kg)
Answer:
speed is equal to distance/time
so 2m/40s
=0.05
25 meters per second.
To find this, divided 150 by 6 in order to get the correct calculation.
Hope this helps!