<span>distance = 360 degrees and the time= 24 hours=1 day
</span><span>Calculate the circumference using D of 16 millions miles and pi
C=50.3 million miles. Using your hint v=(50.3 10^6)/(365.25 x 24 hrs)
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radius of 98 million miles or a diameter of 196 million miles, giving a circumference of 615.75 million miles using the d=rt equation,
v=615.75 million/(365.24 days)=1.69 million miles per day, or .07 million miles per hour.
10 x 4^2 = 160 / 8..
V = 20m/s...
...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.
This is my guess since the problem says 4m/s^2
V= distance/ ST (traveled/used)
Answer:
Explanation:
Distance between proton and electron = r = 5.5 x 10⁻¹³ m
Magnitude of charge on electron and proton = 1.67 x 10⁻¹⁹ C
To find their initial acceleration first force between them is:
Initial acceleration of electron and proton are found using
F=ma
a=F/m
Answer:
Sagittarius A
At its center, surrounded by 200-400 billion stars and undetectable to the human eye and by direct measurements, lies a supermassive black hole called Sagittarius A*, or Sgr A* for short. The Milky Way has the shape of a spiral and rotates around its center, with long curling arms surrounding a slightly bulging disk.
Explanation:
Answer:
The 15 ⁰C measured at this altitude is above the standard temperature for the altitude.
Explanation:
The standard temperature at sea level is 15 degrees Celsius. It decreases about 2 degrees C (or 3.5 degrees F) per 1,000 feet of altitude above sea level.
235 meters is equal to 771 feet.
Using the formula below, we can estimate temperature loss due to this change in altitude, that is 771 feet above sea level.
temperature loss = (3.5 x Change in altitude)/1000ft
temperature loss = (3.5 x 771ft)/1000ft = 2.7⁰F, (32 -2.7 = 29.3 ⁰F)
this is equivalent to 1.5⁰C temperature loss.
Thus, the standard temperature of the engineering quadrangle at 235 meters above sea level is 13.5 ⁰C.
Therefore, the 15 ⁰C measured at this altitude is above the standard temperature for the altitude.