Answer:
the magnitude of the total electric field is 25 V/m
Explanation:
Given data
point above = 0.5 m
charges = 18 V/m
to find out
the magnitude of the total electric field
solution
the magnitude of the total electric field is 25 V/m because number is less than the twice magnitude of field by every charge and the horizontal component in electric field by every charge cancel out and vertical component in field added together
The answer is A. <span>Some work input is used to overcome friction. </span>
The period of any wave is the time it takes for its angle
to go from zero to 2pi .
The 'sin' function is a wave. The angle of this one is (8pi t).
When t=0, the angle is zero.
Wonderful.
Now, how long does it take for the angle to grow to 2pi ?
I*n other words, when is (8pi t) = 2pi ?
Divide each side by '2pi': . . . . . 4 t = 1
Divide each side by ' 4 ': . . . . . t = 1/4
And there you are. Every time 't' grows by 1/4, (8pi t) grows by 2pi.
So if you graph this simple harmonic motion described by 'd', you'll
see the graph wiggle up and down with a period of 1/4 .
Beats.
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats. The beat frequency is equal to the absolute value of the difference in frequency of the two waves.
