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Jlenok [28]
3 years ago
6

Please help me if you can.

Physics
1 answer:
Alex3 years ago
5 0

Answer:

30. $3.85

31. $2.22

Explanation:

30. The time duration of the kitchen clock is left on = All day = 24 hours

The power rating of the kitchen clock, P = 4 watts

The electricity cost in Alberta, R = $0.11 per kilowatt hour

The total number of hours the kitchen clock is on during the year, 't', is given as follows;

t = Number of hours per day × Number of days per year

∴ t = 24 hours/day × 365 days/year = 8,760 hours

The energy consumption of the kitchen clock, per year, E = P × t

∴ E = 4 watts × 8,760 hours = 35,040 watts-hour = 35.040 kw·h

The cost of operating the clock in one year, C = E × R

∴ Operating cost for the kitchen clock

∴ C = 35.040 kw·h × $0.11/(kw·h) = $3.8544 ≈ $3.85

The cost of operating the clock in one year, C ≈ $3.85

31. The power rating of the ghetto blaster, P = 28 watts

The time duration the ghetto blaster was on during an average month = All day = 24 hours

The number of days during an average month, n = 30 days

The cost of electricity in Alberta, R = $0.11 per kilowatt hour

The time in hours the ghetto blaster was on, t = 30 days/month × 24 hours/day

∴ t = 720 hours per month

The cost of operating the ghetto blaster in one month, C = P × t × R

∴ C = 28 W × 720 hours × 1 kw·h/(1000 w·h)× $0.11/(kw·h) = $2.2176

∴ The cost of operating the ghetto blaster in one month, C ≈ $2.22

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Answer: B

Explanation:

A machine multiplies the work output of a something by some amount. In this question, the ax is the machine. Thus, the ax is multiplying the work outputted by the lumberjack, so the answer is B. The reason it is not C is because there could be other forces interacting on the wood which the ax can affect.

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Find the energy released in the fission reaction¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n) The atomic masses of the fission product
ikadub [295]

Fission reaction is given

¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n)

The atomic masses of the fission products are 97.912735 u for ⁹⁸₄₀Zr and 134.916450 u for ¹³⁵₅₂Te. Hence, the energy released in fission reaction is 191.715 MeV.

How to find the energy released in the given fission reaction?

We know, that the atomic mass of the elements are as follows:

  • ⁹⁸₄₀Zr - 97.9120u
  • ¹³⁵₅₂Te - 134.9087u
  • ²³⁵₉₂U  - 235.0483923u
  • n = 1.008665u

In order to find the mass difference, we will calculate the initial mass and the mass of products.

The equation for the reaction:

n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3n

Mass of initial reagents is 1.008665u + 235.0483923u = 233.052588u

Product of the reagents is 97.9120u + 134.9087u + 3(1.008665u) = 235.846773u

Now, using the formula of

E=(\triangledown m)c^2

E=(0.205815u)\frac{931.494MeV/c^2}{u} c^2=191.715MeV

Hence, the energy released in fission reaction is 191.715 MeV.

To learn more about fission reactor, refer to:

brainly.com/question/23276812

#SPJ4

4 0
2 years ago
Jennifer, who has a mass of 50.0 kg, is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to av
Assoli18 [71]

Answer:

Average force = 3.5 kN

Explanation:

Given:

Mass of Jennifer (m) = 50 kg

Initial velocity = 35 m/s

Time taken to stop body = 0.5 s

Find:

Average force

Computation:

v = u + at

0 = 35 + a(0.5)

Acceleration (a) =  - 70 m/s² = 70 m/s²

Average force = ma

Average force = (50(70)

Average force = 3500 N

Average force = 3.5 kN

6 0
3 years ago
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