3 years ago

Secants PR and TR intersect outside of a circle. QS measures 70.15° and ∠ QRS measures 51.68°. Determine the measure of PT.

Mathematics

1 answer:

lozanna [386]3 years ago

8 0

Answer:

nnnnnnnnn

Step-by-step explanation:

Here you go, the same answer you gave me :)

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Step-by-step explanation:

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$D=b^2-4ac\\\Rightarrow D=3^2-4\times 7\times 1\\\Rightarrow D=-19$

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$x=\frac{-b\pm \sqrtD}{2a}\\\Rightarrow x=\frac{-3\pm \sqrt{-19}}{2\times 1}\\\Rightarrow x=-\frac{3}{2}\pm \frac{\sqrt{19}i}{2}\\\Rightarrow x=-\frac{3}{2}+\frac{\sqrt{19}i}{2}, x=-\frac{3}{2}-\frac{\sqrt{19}i}{2}$

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