Answer:
Explanation:
Given
velocity of boat with respect to river
velocity of river is
River is 3.5 km wide
Suppose boat leaves at an angle of with vertical such that it reaches exactly opposite end of initial Point
Therefore
component will balance the river Flowso that sin component helps to cross the river
Answer:
C. greater than D, but less than 2D
Explanation:
The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.
The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.
The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...
v2 = v1·√(1/(1/2)) = v1·√2
This means the second mass will land at a distance of about D√2, a value ...
greater than D but less than 2D.
Hello there!
The formula for Force is F = MA, or
Force = Mass x Acceleration
Well, since we have a rock falling in free fall, we can use the magical number 9.8 m/s^2 (also known as gravity). We have our value for force, 147N (Newtons).
So now, we have the value of our acceleration, A, and our value of the force, F, in our formula.
147 = 9.8M
To solve for M, we need to divide 147 by 9.8.
147/9.8 = 15
This means our Mass is 15 kg (remember your units!)
I hope this helps!
Materials that conduct heat and electricity well in the solid state result when metals bond with metals. <span>This type of bonding is called metallic bonding. Metallic bonding is when positive ions (metals) are in a 'sea of negative electrons'. The electrons are delocalised, which means they can move around easily and carry charge, and this enables it to conduct electricity, even in a solid state.</span>
Answer: F = 3.28 × 10^-7 N
Explanation:
Alpha particle charge (q)= 2e
e = 1.6 × 10^-19
q = 2e = 2 × (1.6 *10^-19) = 3.2 × 10^-19
1/4πEo = 9 × 10^9
Distance(r) = 5.3 × 10^-11m
The force of attraction between the two particles is given by:
F = (1/4πEo) (q1q2 / r^2)
F = [(9 × 10^9) (3.2 × 10^-19) (3.2 × 10^-19)] / (5.3 × 10^-11)^2
F = (92.16 × 10^(9 - 19 - 19)) / 28.09 × 10^-22
F = (92.16 × 10^-29) / 28.09 × 10^-22
F = 3.28 × 10^(-29 + 22)
F = 3.28 × 10^-7 N