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VLD [36.1K]
3 years ago
5

Select the correct answer. Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 ne

wtons while Andy pushes the table from the opposite side with a force of 125 newtons. Ignoring the masses of Eli and Andy, what is the resultant acceleration of the table if its mass is 10.0 kilograms? A. 13.5 meters/second2 B. 0.50 meters/second2 C. 4.0 meters/second2 D. 5.50 meters/second2 E. 1.35 meters/seconds2
Physics
2 answers:
sergiy2304 [10]3 years ago
7 0

Acceleration of the table: B. 0.50 meters/second2

Explanation:

The problem can be solved by using Newton's second law of motion, which states that the net force acting on an object is the product of its mass and its acceleration. Mathematically:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

For the table in this problem, we have:

\sum F = 125 N - 120 N = 5 N is the net force on the table, because there are two forces of 125 N and 120 N acting in opposite  directions

m = 10.0 kg is the mass of the table

Solving for a, we find the acceleration:

a=\frac{\sum F}{m}=\frac{5}{10.0}=0.50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

Ira Lisetskai [31]3 years ago
7 0

Answer:

B. 0.50 meters/second2 for plato

Explanation:

got 10 on the test :)

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We can use the formula of the moment of inertia given by:

r\cdot F=I\alpha

Where:

r = Distance from the point about which the torque is being measured to the point where the force is applied

F = Force

I = Moment of inertia

α = Angular acceleration

So:

\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}

Answer:

12 rad/s²

8 0
1 year ago
A 980 kg roller coaster cart is traveling along a track at 17 m/s before it rolls down a 30 m tall hill (Point A). What will be
MrRissso [65]

The kinetic energy halfway the hill is 2.86\cdot 10^5 J

Explanation:

If there are no friction forces acting on the cart, we can apply the law of conservation of energy: the mechanical energy of the cart (which is the sum of potential energy + kinetic energy) must be conserved. So we can write:

U_A +K_A = U_B + K_B

where

U_A=mgh_A is the initial potential energy, at point A, with

m = 980 kg (mass of the cart)

g=9.8 m/s^2 (acceleration of gravity)

h_A = 30 m (height at point A)

K_A=\frac{1}{2}mv_A^2 is the initial kinetic energy, at point A , with

v_A=17 m/s (velocity at point A)

U_B=mgh_B is the final potential energy, at point B, where

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K_B=\frac{1}{2}mv_B^2 is the final kinetic energy, at point B, where

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Here we are interested in finding K_B, so by re-arranging the equation and substituting we find:

K_B = U_A+K_B-U_B = mg(h_A-h_B)+\frac{1}{2}mv_A^2=(980)(9.8)(30-15)+\frac{1}{2}(980)(17)^2=2.86\cdot 10^5 J

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8 0
3 years ago
Which of the following is an example of Newton's Third Law?* O A stack of pennies will not move unless you flick them over. O Fa
Morgarella [4.7K]

Answer:

A ball hits the ground and the ground pushes up on it

Explanation:

Newton's third law basically states that for every action, there's a reaction.

a ball hitting the ground would be the action. the ground pushing up on it with the same force is the reaction.

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5 0
3 years ago
Please help soon!!!!
anyanavicka [17]
The Answer: Parallel
6 0
3 years ago
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Answer:
a.3.87s
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Step by step explanation:
Refer to the diagram

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