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3 years ago

Which equation can be used to solve for acceleration?

Physics

2 answers:

Diano4ka-milaya [45]3 years ago

7 0

Answer:

the answer is the first one.

Explanation:

one way to find out is if you look at the other equations they are mixed matched. For an example a=d/t should be s= d/t.

antoniya [11.8K]3 years ago

3 0

A = d/t
hope this helps x

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Electromagnetic waves polarized in the x direction propagate towards an ideal polarizer whose axis is aligned with the y-axis. H

Digiron [165]

Answer:

there is ZERO TRANSMISSION through the polarizer.

Explanation:

Given the data in the question;

waves was polarized in the x direction propagate towards an ideal polarizer whose axis is aligned with the y-axis.

so θ = 90° { aligned with the y-axis }

now, we know that for polarized light going at angle θ to the polarizer;

I = I₀ × cos²θ

Where I₀ is the intensity of unpolarized light.

I is the intensity after polarization.

so we substitute the value of θ

I = I₀ × cos²( 90° )

I = I₀ × 0

I = 0

Therefore, there is ZERO TRANSMISSION through the polarizer.

6 0

2 years ago

a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to

Kaylis [27]

The loops must the coil have to generate a maximum emf of 2500 will be 439.

<h3 /><h3>What is the faraday law of electromagnetic induction?</h3>

According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.

Given data;

Area,A = 0.239 m²

Angular velocity,ω=373 rad/sec

Magnetic field,B=0.0639 T

Maximum emf,E= 2500V

The formula for the maximum induced voltage is;

E{max} = N × B × A × ω

2500 = N × 0.639 × 0.0239 × 373

N = 438.66

N = 439 \ turns

Hence, loops must the coil have to generate a maximum emf of 2500 will be 439.

To learn more about the faraday law of electromagnetic induction refer to;

brainly.com/question/26334813

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2 years ago

State two factors that affect the spring constant of a spring made using a wire of a certain material and given thickness

MaRussiya [10]

The spring's rigidity is quantified by the spring constant. The spring constant increases as the wire's thickness increases. The spring constant lowers as the coil's diameter increases.

Material: Steel and copper are two materials that have differing constants when used to make identical springs.

Describe the spring constant ?

The restoring force applied to the spring for a given length of deflection is known as the spring constant. It is often referred to as the amount of force needed to extend or compress a spring one unit of length.

The level of resistance to spring deformation is expressed by the spring constant. In addition to being known as spring stiffness or spring rate, the spring constant and It is represented by the letter "K."

The following variables affect the coil spring's spring constant:-

a) Modulus of rigidity (G): As the modulus of rigidity of the spring material increases, so does the coil spring's spring constant.

b) Wire diameter (d): As the diameter of the spring wire grows, so does the spring constant.

c) Coil diameter (D): As the diameter of the spring coil increases, so does the spring's spring constant.

d) Number of coils (n): As the number of spring coils increases, the spring constant decreases.

To know more about spring constant :

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8 0

1 year ago

Good coding specialists share which of the following characteristics?

Anarel [89]

The correct option is C.
For an individual to become a code specialist, such a person must have advanced computer skills especially in coding processes. The medical field has many sub specialties, therefore a coding specialist must choose to work in a particular area of medicine which interest him most. Such people must also be able to work independently.

5 0

3 years ago

Read 2 more answers

The current theory of the structure of the

Mariana [72]

Answers:

a) $2.82(10)^{21} kg$

b) $1410 J$

c) $36.62 m/s$

Explanation:

<h3>a) Mass of the continent</h3>

Density $\rho$ is defined as a relation between mass $m$ and volume $V$ :

$\rho=\frac{m}{V}$ (1)

Where:

$\rho=2720 kg/m^{3}$ is the average density of the continent

$m$ is the mass of the continent

$V$ is the volume of the continent, which can be estimated is we assume it as a a slab of rock 5300 km on a side and 37 km deep:

$V=(length)(width)(depth)=(5300 km)(5300 km)(37 km)=1,030,330,000 km^{3} \frac{(1000 m)^{3}}{1 km^{3}}=1.03933(10)^{18} m^{3}$

Finding the mass:

$m=\rho V$ (2)

$m=(2720 kg/m^{3})(1.03933(10)^{18} m^{3})$ (3)

$m=2.82(10)^{21} kg$ (4) This is the mass of the continent

<h3>b) Kinetic energy of the continent</h3>

Kinetic energy $K$ is given by the following equation:

$K=\frac{1}{2}mv^{2}$ (5)

Where:

$m=2.82(10)^{21} kg$ is the mass of the continent

$v=4.8 \frac{cm}{year} \frac{1 m}{100 cm} \frac{1 year}{365 days} \frac{1 day}{24 hours} \frac{1 hour}{3600 s}=1(10)^{-9} m/s$ is the velocity of the continent

$K=\frac{1}{2}(2.82(10)^{21} kg)(1(10)^{-9} m/s)^{2}$ (6)

$K=1410 J$ (7) This is the kinetic energy of the continent

<h3>c) Speed of the jogger</h3>

If we have a jogger with mass $m=77 kg$ and the same kinetic energy as that of the continent $1413 J$ , we can find its velocity by isolating $v$ from (5):

$v=\sqrt{\frac{2 K}{m}}$ (6)

$v=\sqrt{\frac{2 (1413 J)}{77 kg}}$

Finally:

$v=36.62 m/s$ This is the speed of the jogger

5 0

3 years ago

Which equation can be used to solve for acceleration? ​

Which equation can be used to solve for acceleration?