The charge density of the sheet is 1.384×10⁻⁷C/m².
Charge density is defined as the charge per unit area.
The sheet is a square of length l=17 cm.
Calculate the area A of the sheet .

The charge Q on the sheet is

The charge density σ is given by,

Substitute 4×10⁻⁹C for Q and 0.0289 m² for A.

Thus, the charge density of the sheet is <u>1.384×10⁻⁷C/m².</u>
λ = 2 m.
The easiest way to solve this problem is using the equation of frecuency of a wave f = v/λ, where v is the velocity of the wave, and λ is the wavelength.
To calculate the wavelength of a microwave light travels through a liquid, it moves at a speed of 2.2 x 10⁸ m/s. If the frecuency of the light wave is 1.1 x 10⁸ Hz, we have to clear λ from the equation f = v/λ:
f = v/λ -------> λ = v/f
λ = 2.2 x 10⁸ m/s / 1.1 x 10⁸ Hz
λ = 2 m (wavelength of the microwave)
The work done by the force is 47.1 J
Explanation:
The work done by a force in moving an object is given by
(1)
where
F is the magnitude of the force
d is the distance covered by the object
is the angle between the direction of the force and the motion of the object
In this problem, the force applied to the object is
F = 3.0 N
This force is always tangential to the track: this means that at every instant, the force is parallel to the motion of the object, so

And the distance covered is equal to the circumference of the circle, which is:

where r = 2.5 m is the radius.
Now we can substitute into eq.(1) to find the work done:

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Answer:
Frequency = f = 10.0394 (1/s)
Explanation:
The frequency of oscillation of the system is given by the action:
f= √(k/m)
f= system count
k = spring constant
m = mass connected to the spring
Therefore the frequency will be:
f= √(k/m) = √(383(N/m) / (3.8kg))= √( 100.7895 (kg×m/s²)/(kg ) =
= √( 100.7895 (1/s²) = 10.0394 (1/s)