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djverab [1.8K]
2 years ago
6

I’ll give brainliest

Physics
1 answer:
liberstina [14]2 years ago
8 0
Cells that are located in the Eukarya domain contain nuclei. So there you have it, your answer is Eukarya!

If you need any further assistance, feel free to PM me or comment on my wall!

P.S. I need one more brainliest to reach Virtuoso, would be much appreciated. <3

- Sofie
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An object is at rest in front of a compressed spring. It travels over a surface that exerts a kinetic frictional force on it and
PolarNik [594]

Answer:

the object will travel 0.66 meters before to stop.

Explanation:

Using the energy conservation theorem:

E_i+K_i+W_f=K_f+U_f

The work done by the friction force is given by:

W_f=F_f*d\\W_f=\µ*m*g*d\\W_f=0.35*4*9.81*d\\W_f=13.7d[J]

so:

\frac{1}{2}1800*(10*10^{-2})+0-13.7d=0+0\\d=0.66m

3 0
3 years ago
Find the distance in nm between two slits that produces the first minimum for 410-nm violet light at an angle of 14.5°.
Galina-37 [17]

Answer:

820 nm

Explanation:

We are given that

Wavelength=\lambda=410 nm

\lambda=410\times 10^{-9} m

1nm=10^{-9} m

\theta=14.5^{\circ}

For first minimum therefore

m=0

We know that for destructive interference

(m+\frac{1}{2})\lambda=dsin\theta

Substitute the values

(0+\frac{1}{2})\times 410\times 10^{-9}=dsin 14.5

d=\frac{410\times 10^{-9}}{2\times sin 14.5}

d=820\times 10^{-9} m=820 nm

Hence, the distance between two slits that produces the first minimum=820 nm

5 0
2 years ago
Read 2 more answers
A stationary 15 kg object is located in a table near the surface of the earth. The coefficient of static friction between the su
Marta_Voda [28]

The net force acting on the object perpendicular to the table is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the object. Then

F[normal] = mg = (15 kg) (9.8 m/s²) = 147 N

The maximum magnitude of static friction is then

0.40 F[normal] = 58.8 N

which means the applied 40 N force is not enough to make the object start to move. So the object has zero acceleration and does not move.

8 0
2 years ago
A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 3240 meters away
Alik [6]
4.5 seconds you devoured 3240/720=4.5
7 0
2 years ago
Read 2 more answers
suppose you increase your walking speed from 5m/s to 14m/s in a period of 1 . what is your acceleration?
Ne4ueva [31]

Acceleration = (change in speed) / (time for the change.

change in speed = (ending speed) - (starting speed)  =  9 m/s.

Acceleration  =  (9 m/s) / (period of 1) .

We don't know the units of the 'period of 1'.
If it means '1 second', then the acceleration is   9 m/s² .

7 0
3 years ago
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