This is a sneaky trick question, to help you discover whether you know
one of the differences between velocity and speed.
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If you make a list of the distances and directions, and ignore the times,
you find these:
4 - west, (3 + 1) - east . . . . . zero in the east/west direction
1.5 - north, 1.5 - south . . . . . zero in the north/south direction
This jogger went out, had a nice jog around the neighborhood,and ended up exactly where he started.
Average velocity = (distance between start point and end point) / (time)
IF the question asked for average SPEED, then you would need the total distance, and divide it by the total time. But it asks for VELOCITY, and <u>that</u> only involves the straight distance between the start point and the end point, regardless of the route taken in between.
The jogger ended up exactly where he started. The distance between start and end points was zero. Average velocity is (zero) / (time) . And that fraction is going to be <em><u>Zero</u></em>, no matter how long or how short the trip was, and no matter how much time it took.
Answer:
The jet will fly 2400 km.
Explanation:
Given the velocity of the jet flying toward the east is 1,500 kmph toward the east.
We need to find the distance covered in 1.6 hours.
In our problem we are given speed and time, we can easily determine the distance using the following formula.
So, the supersonic jet will travel 2400 km in 1.6 hours toward the east from its starting point.
Answer:
Any force greater than 24.5 N
Explanation:
To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.
I hope I helped correct me if im wrong
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When an object gets heated by a temperature ΔT energy needed, E = mcΔT
Here mass of glass = 55 g =
Change in temperature ΔT = 16^0C[/tex] = 16 K
Specific heat of glass = 0.84 J/gK = 840 J/kgK
Substituting we will get
E = *840*16 = 739.2 J
So a heat of 739.2 J is required to raise the temperature of a 55 g glass ball by 16°C