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NemiM [27]
3 years ago
11

Where can I take a virtual hike for the following assignment?: (ITS FOR OUTDOOR EDUCATION; BUT AGAIN THERE IS NO SUBJECT LABELED

AS THAT)
03.03 Take a Hike Assignment Instructions

1. Take a walk/hike on a trail you've never hiked before. Remember that you can use a map or online resource to help you locate nature trails in your area.
2. Take photos of your experience on the walk. Examples of what to photograph include: trees and plants, animals, insects, litter or other evidence of man, and the supplies you brought on your hike. Be sure at least one photograph shows you on the trail.
3. Write a reflection of your experience on the hike/walk. The written reflection should include:
observations of what you saw and experienced
whether or not your supplies were adequate for your hike
what you enjoyed about the hike and anything that was new for you
comparison of this walk to a previous hike/walk
4. Compose a presentation (web-based or slideshow) that includes the written reflection and four to six photos from your walk.
5. Submit the completed presentation to your instructor as assignment 03.03 Take a Hike.
Physics
1 answer:
rosijanka [135]3 years ago
4 0
You might just have to take a walk outside instead of a virtual one beside its healthier for you also what kind of area do you live in 
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valkas [14]
This is a Fraunhofer single slit experiment, where the light passing through the slit produces an interference pattern on the screen, and where the dark bands (minima of diffraction) are located at a distance of
y= \frac{m\lambda D}{a}
from the center of the pattern. In the formula, m is the order of the minimum, \lambda the wavelenght, D the distance of the screen from the slit and a the width of the slit.

In our problem, the distance of the first-order band (m=1) is y=0.22 cm. The distance of the screen is D=86 cm while the wavelength is \lambda = 384 nm=384 \cdot 10^{-7}cm. Using these data and re-arranging the formula, we can find a, the width of the slit:
a= \frac{m \lambda D}{y}= \frac{1 \cdot 384 \cdot 10^{-7}cm \cdot 86 cm}{0.22 cm}=0.015 cm
3 0
3 years ago
Compare the signs of ƒ for lenses and mirrors.
STALIN [3.7K]

Answer:

simple

Explanation:

<h3>CONCAVE MIRRORS AND LENSES</h3>

<h3>f= negative</h3>

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3 0
3 years ago
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A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple
aliina [53]

Answer:

T= 1 s

Explanation:

Given that

When x=  cm ,T= 1

we know that time period of spring mas system given as

T=2\pi \sqrt{\dfrac{m}{k}}

T= Time period

m= mass

k=spring constant

So from above equation we can say that time period of system does not depends on the value of x.

So when x= 10 cm ,still time period will be 1 s.

T= 1 s

5 0
3 years ago
A space station, in the form of a wheel 140 m in diameter, rotates to provide an "artificial gravity" of 3.90 m/s2 for persons w
Zigmanuir [339]
Radial acceleration is given by

a_{rad}= \frac{v^2}{r}
where 

v=r \omega
then

a_{rad}= \frac{r^2 \omega^2}{r}=r\omega^2

Now

70\omega^2=3.90 \frac{m}{s^2}  \\  \\ \omega= \sqrt{ \frac{3.9}{70} }

Using the relation

\omega=2 \pi f

2 \pi f= \sqrt{ \frac{3.9}{70} }\\  \\ f= \frac{1}{2 \pi}\sqrt{ \frac{3.9}{70} }Hz

Putting into rpm

\frac{60}{2 \pi}\sqrt{ \frac{3.9}{70}} =2.254rpm

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3 years ago
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Artyom0805 [142]
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Uranus' atmosphere is mostly hydrogen and helium, with a small amount of methane and traces of water and ammonia.

As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.

10. 24,622 km

Neptune has an average temperature of -353 Fahrenheit (-214 Celsius).

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