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NemiM [27]
3 years ago
11

Where can I take a virtual hike for the following assignment?: (ITS FOR OUTDOOR EDUCATION; BUT AGAIN THERE IS NO SUBJECT LABELED

AS THAT)
03.03 Take a Hike Assignment Instructions

1. Take a walk/hike on a trail you've never hiked before. Remember that you can use a map or online resource to help you locate nature trails in your area.
2. Take photos of your experience on the walk. Examples of what to photograph include: trees and plants, animals, insects, litter or other evidence of man, and the supplies you brought on your hike. Be sure at least one photograph shows you on the trail.
3. Write a reflection of your experience on the hike/walk. The written reflection should include:
observations of what you saw and experienced
whether or not your supplies were adequate for your hike
what you enjoyed about the hike and anything that was new for you
comparison of this walk to a previous hike/walk
4. Compose a presentation (web-based or slideshow) that includes the written reflection and four to six photos from your walk.
5. Submit the completed presentation to your instructor as assignment 03.03 Take a Hike.
Physics
1 answer:
rosijanka [135]3 years ago
4 0
You might just have to take a walk outside instead of a virtual one beside its healthier for you also what kind of area do you live in 
You might be interested in
A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light.
kirill [66]

Answer:

The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

Explanation:

Given:

(A)

Current I = 1 A

Voltage V = 12 V

For finding the resistance,

  V = IR

  R = \frac{V}{I}

  R = \frac{12}{1}

  R = 12Ω

(B)

For finding power delivered,

  P = I^{2} R

  P = (1) ^{2} \times 12

  P = 12 Watt

(C)

For finding the potential difference,

   V = IR

   V = 5 \times 10^{-3} \times 2

   V = 10 \times 10^{-3}

   V = 0.01 V

Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

4 0
3 years ago
A bottle lying on the windowsill falls off and takes 4.95 seconds to reach the ground. The distance from the windowsill to the g
Liula [17]
The distance an object falls from rest through gravity is 
                        D  =  (1/2) (g) (t²) 
           Distance  =  (1/2 acceleration of gravity) x (square of the falling time)

We want to see how the time will be affected 
if  ' D ' doesn't change but ' g ' does. 
So I'm going to start by rearranging the equation
to solve for ' t '.                                                      D  =  (1/2) (g) (t²)

Multiply each side by  2 :         2 D  =            g    t²  

Divide each side by ' g ' :      2 D/g =                  t² 

Square root each side:        t = √ (2D/g)

Looking at the equation now, we can see what happens to ' t ' when only ' g ' changes:

  -- ' g ' is in the denominator; so bigger 'g' ==> shorter 't'

                                             and smaller 'g' ==> longer 't' .-- 

They don't change by the same factor, because  1/g  is inside the square root.  So 't' changes the same amount as  √1/g  does.

Gravity on the surface of the moon is roughly  1/6  the value of gravity on the surface of the Earth.

So we expect ' t ' to increase by  √6  =  2.45 times.

It would take the same bottle  (2.45 x 4.95) = 12.12 seconds to roll off the same window sill and fall 120 meters down to the surface of the Moon.
5 0
3 years ago
41. Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 h
romanna [79]

Answer:

138.3 days

Explanation:

Given that a Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 has been discovered and has a radius of 7.8 X 10 meters.

The period of time for Clayton J-21 to orbit Dayli can be calculated by using Kepler law.

T^2 is proportional to r^3

That is,

T^2/r^3 = constant

98^2 / 62^3 = T^2 / 78^3

Make T^2 the subject of formula.

T^2 = 98^2 / 62^3 × 78^3

T^2 = 19123.2

T = sqrt ( 19123.2 )

T = 138.2867 days

Therefore, the period of time for Clayton J-21 to orbit Dayli is 138.3 days approximately.

4 0
3 years ago
All of the following are regulated by the medulla except
Fantom [35]

Answer:

D. flight or flight response.

Explanation:

im 99.999999% sure im right.

hey

vegan mac n cheese

always has been

6 0
3 years ago
Which statement about gravity is true?
SVETLANKA909090 [29]

Out of the given options, ‘it is described as a fundamental force and therefore does not depend on other forces’ is the true statement about gravity.

Answer: Option B

<u>Explanation: </u>

As we all know that there are four fundamental forces existing in the universe- Electromagnetic force, strong forces, weak forces and the gravitational force.

These are the forces that don’t depend on any other physical force to draw a considerable impact on the physical objects. The gravitational force can be defined as,

                     F=G \times \frac{m_{1} m_{2}}{r^{2}}

Where,

G = Gravitational Constant

m_{1} , m_{2} = Masses of two substances under consideration

R = distance between the two substances.

Looking upon the formula of gravitational force we can easily estimate that the gravitational force relies on the mass of substances and the relative distance between them. There is no factor than the air friction that hinders the gravitational force and that too in a negligible amount.

5 0
3 years ago
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