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Alekssandra [29.7K]
3 years ago
15

What force is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic fr

iction between the sled and the ground is 0.25?
Physics
1 answer:
Igoryamba3 years ago
3 0

Answer:

Any force greater than 24.5 N

Explanation:

To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.

I hope I helped correct me if im wrong

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Answer:

B. A wave of visible light is produced.

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4 years ago
Calculate the voltage (in volts) of a solar cell that generates a current of 139 milliamps and has a resistance of 6 ohms.
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Answer:

834 milli-volts

Explanation:

Data provided in the question:

Current = 139 milliamps = 139 × 10⁻³ A

resistance = 6 ohms

Now,

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on substituting the respective values, we get

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3 years ago
Jake drags a sled of mass 25 kg across the snow. The sled is attached to a rope that pulls with a force of 50 N at an angle of 3
madam [21]

Answer:

218.5 N

Explanation:

In order for the sled to be in equilibrium along the vertical direction, the forces acting along this direction must be balanced. So the equilibrium equation is:

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\theta is the angle between the force and the horizontal, so

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(mg) is the weight of the sled, with

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