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2 years ago

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Mathematics

2 answers:

antoniya [11.8K]2 years ago

5 0

Answer is 1 (space fillersqllelrlfkxkwkekfnjcxk)

Juli2301 [7.4K]2 years ago

4 0

Answer:

Step-by-step explanation:

m [slope] = ∆y/∆x = y₂-y₁/x₂-x₁

m [slope] = 9 - 6 / 4 - 1 = 3 / 3 = 1

The equation for this relationship is

y = x + 5

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ANSWER ASAP!

AleksandrR [38]

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2 years ago

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PLEASE HELP ASAP !! (Picture included)

slega [8]

This is the question that's gonna put me over the top and make me a Brainly Genius. Of course working for free doing middle school math homework doesn't really sound like a genius, but I'm doing it anyway.

This one is the Pythagorean Theorem of course:

$(x+3)^2 + (x+4)^2 = (x+10)^2$

$x^2 + 6x + 9 + x^2 + 8x + 16 = x^2 + 20 x + 100$

$x^2 - 6x - 75 = 0$

The Shakespeare Quadratic Formula (2b or -2b) is a little shortcut for the quadratic formula when the middle term is even.

$x^2-2bx+c \textrm{ has zeros } x=b\pm \sqrt{b^2-c}$

So we get

$x = 3 \pm \sqrt{3^2 -(-75)} = 3 \pm \sqrt{84} = 3 \pm 2 \sqrt{21}$

The minus root is less than -6 giving negative sides, so we reject it and conclude

$x = 3 + 2 \sqrt{21}$

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3 years ago

Find the value of x help 10 points

MrRissso [65]

<u>Answer:</u>

x = 5.67

<u>Step-by-step explanation:</u>

We are given a right angled triangle with a length of the hypotenuse 8 with the remaining two sides (base and perpendicular) that are equal to each other.

Assuming the two equal legs of this right angled triangle to be x, we can use the Pythagoras Theorem to find the value of x.

$(x)^2+(x)^2=(8)^2$

$2x^2=64$

Taking square root at both the sides to get:

$\sqrt{2x^2} =\sqrt{64}$

$1.41x=8\\\\x=5.67$

Therefore, x = 5.67.

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3 years ago

Find the total area of the figure below.

Maksim231197 [3]

176 square yards

Step-by-step explanation:

The picture of the question in the attached figure N 1

we know that

The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)

see the attached figure N 2 to better understand the problem

step 1

Find the area of the two trapezoids (#1 and #2)

simplify

we have

substitute

step 2

Find the area of the two smaller rectangles (#3 and #4)

we have

substitute

step 3

Find the area of the walkway around the rectangular pool

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2 years ago

The two shortest sides of a right triangle are 10 in. And 24 in. long. What is the length of the shortest side of a similar righ

ivanzaharov [21]

If the two shortest sides of the triangle are 10in and 24in, then using Pythagoras' theorem, the longest side =
$\sqrt{10^2 + 24^2}$
= $\sqrt{676}$
= $26$

Now we know the two longest sides of the first triangle (24in and 26in) we can compare them with the two longest sides of the second triangle.
If $x$ = the scale factor the first triangle is enlarged by then
$26x = 39$ and $24x = 36$
⇒ $x = 1.5$

Finally, we need to multiply the smallest side of the first triangle by the scale factor to find the shortest side of the second triangle.
$10(1.5) = 15$
So the length of the shortest side of the other triangle is 15in.

You could, instead, calculate the length of the shortest side of the second triangle by using Pythagoras' theorem and ignoring the first triangle completely.

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