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ivanzaharov [21]
2 years ago
10

Sana loved swimming.She joined a new smimmimg club .When she looked at the floor of the pool to estimate its depth she found tha

t it was shallow .But when she dived in the pool she found out that the pool was quiet deep.Write down the scientific reason for this situation?
Physics
1 answer:
melisa1 [442]2 years ago
6 0

Answer:

Refraction

Explanation:

When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.

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A racecar driver has to hold on tightly when going around a banked curve. Approximately what is the centripetal force on a 2220.
g100num [7]

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4 0
3 years ago
A mass m at the end of a spring oscillates with a frequency of 0.89 hz. when an additional 603 g mass is added to m, the frequen
MrMuchimi

The solution for this problem:

Given:

f1 = 0.89 Hz

f2 = 0.63 Hz

Δm = m2 - m1 = 0.603 kg 


The frequency of mass-spring oscillation is: 
f = (1/2π)√(k/m) 
k = m(2πf)² 

Then we know that k is constant for both trials, we have: 
k = k 


m1(2πf1)² = m2(2πf2)² 

m1 = m2(f2/f1)² 


m1 = (m1+Δm)(f2/f1)² 


m1 = Δm/((f1/f2)²-1)

 m 1 = 0.603/ (0.89/0.63)^2 – 1

= 0.609 kg or 0.61kg or 610 g

5 0
3 years ago
Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH = 1.06
Slav-nsk [51]

Answer:

1.06085\times 10^{-10}\ m

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

m = Mass of electron = 9.11\times 10^{-31}\ kg

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

e = Charge of electron = 1.6\times 10^{-19}\ C

n = 1 (ground state)

Angular momentum is given by

L=mvr

From Bohr's atomic model we have

L=\dfrac{nh}{2\pi}

mvr=\dfrac{nh}{2\pi}\\\Rightarrow v=\dfrac{nh}{2\pi mr}

The centripetal force will balance the electrostatic force

\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m

The diameter is 2\times 5.30426\times 10^{-11}=1.06085\times 10^{-10}\ m

7 0
3 years ago
2. A ball tied to a pole by a rope swings in a circular path with a centripetal acceleration of 2.7 m/s. If the ball has a
Helga [31]

Answer: The diameter of the circular path is 2.96m

Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.

Centripetal acceleration = 2.7m/s^2

Tangential speed = 2.0m/s

Radius = 2.0^2 / 2.7 = 4/2.7

= 1.48m

Diameter = radius*2

= 1.48*2 = 2.96m.

3 0
3 years ago
I really don’t get this one
worty [1.4K]

Compounds are molecules with 2 or more elements

So the answer would be the third one

CO2;H2O

4 0
2 years ago
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