Answer:
Ka = 1.78 × 10⁻⁵
Explanation:
Let's consider the following thermochemical equation.
CH₃COOH(aq) + H₂O(l) → CH₃COO⁻(aq) + H₃O⁺(aq) ∆G° = 27.1 kJ/mol
At 25°C (298 K), we can find the equilibrium constant (Ka) using the following expression.
∆G° = - R × T × lnKa
where,
R: ideal gas constant
T: absolute temperature
27.1 × 10³ J/mol = - (8.314 J/K.mol) × 298 K × lnKa
Ka = 1.78 × 10⁻⁵
Answer:
calcium 20. charge of calcium is +2
2,8,8,2 is elecrons arrangement in the outermost shell.2 electrons in the outermost shell easily remove it. And form stable cations.
Explanation:
The answer is
A the ants climbed up the table
The Nernst equation allows us to predict the cell potential for voltaic cells under conditions other than the standard conditions of 1M, 1 atm, 25°C. The effects of different temperatures and concentrations may be tracked in terms of the Gibbs energy change ΔG. This free energy change depends upon the temperature & concentrations according to ΔG = ΔG° + RTInQ where ΔG° is the free energy change under conditions and Q is the thermodynamic reaction quotient. The free energy change is related to the cell potential Ecell by ΔG= nFEcell
so for non-standard conditions
-nFEcell = -nFE°cell + RT InQ
or
Ecell = E°cell - RT/nF (InQ)
which is called Nernst equation.