Answer: The system will try and offset the change.
Explanation: Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in a direction to minimize the effect.
Thus if temperature is increased, the reaction will shift in a direction where temperature is decreasing and vice versa. Similarly if pressure is increased, the reaction will shift in a direction where pressure is decreasing and vice versa.
Answer 1)

+

----> 2 HCl
This is a pure
chemical reaction that is taking place.
In this reaction the two chemical species which are Chlorine and Hydrogen undergo addition reaction and form two moles of hydrochloric acid. No new species is formed except the combination of reactants which gives the product.
Answer 2) H + H ----> He + n
This is a nuclear reaction.
As the reactant species is undergoing a reaction which is resulting in formation of new species completely different than the elements in reactants.
Also there is a neutron which is generated after the reaction this is clear indication of nuclear fusion reaction. Hence, it can be called as nuclear reaction.
The valence electron determines whether an ionic or covalent bond develops between two atoms.
An atom's outer shell electrons, known as valence electrons, can take a role in the creation of chemical bonds. When two atoms establish a single covalent bond, normally, both atoms contribute one valence electron to create a shared pair.
Ionic bonds, also known as electrovalent bonds, are a type of linkage created in a chemical molecule by the electrostatic attraction of ions with opposing charges. When one atom's valence (outermost) electrons are permanently transferred to another atom, a bond of this kind is created. The one or two and three are lost and gained in ionic bond formation, but particles with four valence electrons are neither lost nor gained. The four electrons are generally shared to form a covalent bond.
Hence, the valence electron decides the type of the bond.
To know more about Electrostatic attraction.
brainly.com/question/14889552
#SPJ4
Answer : The heat of combustion of n-propanol is 0.554 kJ/mol
Explanation :
First we have to calculate the moles of n-propanol.

Molar mass of n-propanol = 60.09 g/mole

Now we have to calculate the heat of combustion of n-propanol.
As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ
So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)
= 0.554 kJ/mol
Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol