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GrogVix [38]
2 years ago
5

Predict the sign of ΔSsys for each process: (b) Hot air expands.

Chemistry
1 answer:
mars1129 [50]2 years ago
8 0

The sign of ΔSsys for hot air expands is positive.

Entropy (S) is the degree of randomness or disorderliness in a thermodynamic system. The randomness increases when the motion of molecules increases due to the addition of heat. It also increases when the distance between the molecules increases.

ΔS is a measurement of the change in entropy in a thermodynamic system. It is positive when entropy increases and negative when it decreases.

When the hot air expands the distance between the molecules of the gas increases and thus the randomness also increases. Entropy increases and the of  ΔS becomes positive.

If you need to learn more about ΔSsys signs, click here

brainly.com/question/13991635

#SPJ4

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3 years ago
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What is the ground-state electron configuration of a neutral atom of manganese?.
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Answer:

Vapor pressure of solution → 151.1 Torr

Option 2.

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Raoult's Law is relationed to colligative property about vapor pressure. A determined solute, can make, the vapor pressure of solution decreases.

ΔP = P° . Xm

where Xm is the mole fraction of solute, P° (vapor pressure of pure solvent)

and ΔP = Vapor pressure of pure solvent - Vapor pressure of solution.

In order to determine the vapor pressure of solution, we need to determine, the vapor pressure of B and A in the solution

B's pressure = P° B . Xm

When we add A to B, A works as the solute and B, as the solvent.

Vapor pressure of pure B is 135 torr. (P° B)

In order to determine, the Xm, we use the moles of A and B

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Vapor pressure of solution = 42.3 Torr + 108.81 Torr → 151.1 Torr

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