What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature and pressure?
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Answer:
a) Binding Energy = 1084.266 MeV
b) Binding energy per nucleon = 8.28 MeV
Explanation:
Binding Energy,
Where ΔM = Mass defect of Iodine-131
The mass of iodine-131 = 130.906124 u.
Number of protons in Iodine-131 = 53
Number of neutrons in Iodine-131 = 78
Mass of a proton = 1.007276 u
Mass of neutron = 1.008664 u
Total mass of the 53 protons in Iodine-131 = (53*1.007276)
Total mass of the 53 protons in Iodine-131 = 53.39 u
Total mass of the 78 protons in Iodine-131 = (78*1.008664)
Total mass of the 78 protons in Iodine-131 = 78.68 u
Binding Energy = 1.164 * 931.5
Binding Energy = 1084.266 MeV
b) Binding Energy per nucleon
The mass of the nucleon of iodine 131 = 130.906124
Binding Energy per nucleon = 1084.266/130.906124
Binding energy per nucleon = 8.28 MeV