Answer:
No.
Explanation:
The spare tire is also moving at the speed of the jeep. When it separates from the jeep, both will be moving at the same horizontal speed, only that the spare tire will also fall at the same time. This if we neglect air friction, that could be a problem since it could cancel the horizontal velocity of the spare tire, although the jeep is blocking most of the air for the spare tire to feel any significant effect in such a short time.
Answer:
9. The Sun's Gravity
10. The core is the densest layer
Let's use Newton's Law of Second Motion: F=ma. When no other direct force is acting on the system, the acceleration is due to the gravity. The modified equation becomes: F = mg. So, yes, you need to take into account the gravitational accelerations in the moon and on Earth.
g,moon = 1.622 m/s²
g,Earth = 9.81 m/s²
The net force is the tension of the string:
F,Earth - F,moon = Tension
Tension = (1/1000 kg)(9.81 m/s²) - (1/1000 kg)(1.622 m/s²)
Tension = 8.188×10⁻³ N
To convert, 1 pound force is equal to 4.45 Newtons:
Tension = 8.188×10⁻³ N * 1 lbf/4.45 N
Tension = 1.84×10⁻³ lbf
Below are the chocies
A. The pendulum is at its highest point.
<span>B. The pendulum is 0.9 m above its lowest point. </span>
<span>C. The pendulum is between its highest and lowest points. </span>
<span>D. The pendulum is at its lowest point.
</span>
I think the answer is C..
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Answer:
The current in the circuit at a time interval of τ seconds after the switch has been closed is 0.123 A
Explanation:
The time constant for an R and C in series circuit is given by τ = RC.
R = 3000 ohms, C = 0.5 × 10⁻⁶ F = 5.0 × 10⁻⁷ F
τ = 3000 × 5 × 10⁻⁷ = 0.015 s
The voltage across a capacitor as it charges is given be
V(t) = Vs (1 - e⁻ᵏᵗ)
where k = 1/τ
At the point when t = τ, the expassion becomes
V(t = τ) = 1000 (1 - e⁻¹) = 0.632 × 1000 = 632 V
Current flows as a result of potential difference,.
Current in the circuit at this time t = τ is given by
I = (Vs - Vc)/R
Vs = source voltage = 1000 V
Vc = Voltage across the capacitor = 632 V
R = 3000 ohms
I = (1000 - 632)/3000 = 0.123 A
