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Liono4ka [1.6K]
3 years ago
14

Test Number 2: This test tests how smart the users on the website is C=5/9(F−32)

Mathematics
1 answer:
joja [24]3 years ago
4 0

Step-by-step explanation:

c=5/9(f-32) can also be written as c = 5(f - 32)/9.

Multiply each side by 9.

That gives us 9c = 5(f - 32).

Apply distributive rule on the right side.

 

9c = 5f - 160

Add 160 to the left side.

9c + 160 = 5f

Lastly, divide both sides 5.

(9c + 160)/5 = f

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A high school track is shaped as a rectangle with a half circle on either side. Jasmine plans on running TWO laps. How many yard
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880 yards

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F. By definition, two shapes are congruent if you can map one onto the other using rigid
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8x+4 (4x+3) = 4 (6x+4)-4 help
Tasya [4]

Answer:

0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x+4(4x+3)=4(6x+4)−4

8x+(4)(4x)+(4)(3)=(4)(6x)+(4)(4)+−4(Distribute)

8x+16x+12=24x+16+−4

(8x+16x)+(12)=(24x)+(16+−4)(Combine Like Terms)

24x+12=24x+12

24x+12=24x+12

Step 2: Subtract 24x from both sides.

24x+12−24x=24x+12−24x

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Step 3: Subtract 12 from both sides.

12−12=12−12

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4 0
3 years ago
Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. A marble is
Reptile [31]

Answer:

a)2/7

b)1/2

c)9/14

d)6/7

Step-by-step explanation:

The jar contains 4 red marbles, numbered 1 to 4 which means

Red marbles = (R1) , (R2) , (R3) , (R4)

It also contains 10 blue marbles numbered 1 to 10 which means

Blue marbles = (B1) , (B2) , (B3) , (B4) , (B5) , (B6) , (B7) , (B8) , (B9) , (B10) .

We can calculate total marbles = 4red +10 blues

=14marbled

Therefore, total marbles= 14

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10) =7

Total number of Blue marbles = 10

Blue and even marbles = 5

(a) The marble is red

P(The marble is red)=total number of red marbles/Total number of marbles

=4/14

=2/7

(b) The marble is odd-numbered

Blue marbles with odd number= (B1) , (B3) , (B5) , (B7) , (B9) ,

Red marbles with odd number = (R1) , (R3)

Number of odd numbered =(5+2)=7

P(marble is odd-numbered )= Number of odd numbered/ Total number of marbles

P(marble is odd-numbered )=7/14

=1/2

(C) The marble is red or odd-numbered?

Total number of red marbles = 14

Number of red and odd marbles = 2

The marbles that has odd number = (R1) , (R3) ,(B1) , (B3) , (B5) , (B7) , (B9) =7

n(red or even )= n(red) + n(odd)- n(red and odd)

=4+7-2

=9

P(red or odd numbered)= (number of red or odd)/(total number of the marble)

= 9/14

(d) The marble is blue or even-numbered?

Number of Blue and even marbles = 5

Total number of Blue marbles = 10

Number of blue that are even= 5

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10)

=7

n(Blue or even )= n(Blue) + n(even)- n(Blue and even)

= 10+7-5 =12

Now , the probability the marble is blue or even numbered can be calculated as

P(blue or even numbered)= (number of Blue or even)/(total number of the marble)

= 12/14

= 6/7

6 0
3 years ago
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