The total cost for a car with 30 miles is $20.00.

First, do 0.5 × 30 because you need to find out how much it will cost. This will give you 15. From there, add the flat rate. 15 + 5 = 20, so it will cost $20.00.

3 0

4 years ago

Read 2 more answers

Need Help balancing the 3 questions on top

Scrat [10]

Answer:

4Na + 1O2 > 2Na2O

SF6 > 1S + 3F2

2FE2O3 > 4FE + 3O2

Step-by-step explanation:

1. Identify the Products and Reactants(always do O2 last)

2. determine how many atoms of each element are present on each side of the equation

3. Add Coefficients and never change the subscripts. If there's a coefficient in front of any compound, it is distributed to both elements.

4. find the total number of atoms on both sides of the equation and make sure they equal with each other

7 0

4 years ago

Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

7 0

3 years ago