Question

You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.

Answer 1

Answer:

Explanation:

A ) initial velocity u = 12 m /s

final velocity v = 6 m /s

height = h

acceleration = - g = - 9.8 m /s²

v² = u² - 2gh

6² = 12² - 2 x 9.8 x h

h = 5.51 m

B )

Let the final velocity when energy becomes half be V at height H

kinetic energy at height h = 1/2 m V²

Given ,

.5 x 1 / 2 m x 12² = 1/2 m x V²

V² = 12² / 2

V = 8.486 m /s

V² = u² - 2 gH

8.486² = 12² - 2 x 9.8 x H

H = 3.67 m .