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jasenka [17]
2 years ago
11

What makes the periodic table arrangement so unique and useful?​

Chemistry
1 answer:
Zepler [3.9K]2 years ago
8 0
Elements are ordered from left to right, increasing atomic number as they go. The periodic table allows us to find out and predict things about elements that haven’t been discovered yet!
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A football is inflated to 12psi at 20°C What is the new pressure in the football
Radda [10]

Answer: The new pressure is 3 psi.

Explanation:

Given: P_{1} = 12 psi,         T_{1} = 20^{o}C

P_{2} = ?,          T_{2} = 5^{o}C

Formula used is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi

Thus, we can conclude that the new pressure is 3 psi.

7 0
3 years ago
Look at a list of the elements or a periodic table. Identify some pairs of elements that you have heard of that have similar pro
igomit [66]

Answer: iron, metal, crystals

Explanation:

8 0
2 years ago
Hi. i need help with this. i lack with this subject
Vesnalui [34]

Answer: It's the circulatory system

Explanation:

8 0
2 years ago
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How many moles of FeS2 are required to produce 32 g of So2
Anna11 [10]

Answer:

So, the right answer is. No. of moles of FeS₂ = 0.25 mole. Explanation: From the balanced. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2.

Explanation:

3 0
2 years ago
Suppose 6.63g of zinc bromide is dissolved in 100.mL of a 0.60 M aqueous solution of potassium carbonate. Calculate the final mo
Alenkasestr [34]

Answer:

[Zn²⁺] = 4.78x10⁻¹⁰M

Explanation:

Based on the reaction:

ZnBr₂(aq) + K₂CO₃(aq) → ZnCO₃(s) + 2KBr(aq)

The zinc added produce the insoluble ZnCO₃ with Ksp = 1.46x10⁻¹⁰:

1.46x10⁻¹⁰ = [Zn²⁺] [CO₃²⁻]

We can find the moles of ZnBr₂ added = Moles of Zn²⁺ and moles of K₂CO₃ = Moles of CO₃²⁻ to find the moles of CO₃²⁻ that remains in solution, thus:

<em>Moles ZnB₂ (Molar mass: 225.2g/mol) = Moles Zn²⁺:</em>

6.63g ZnBr₂ * (1mol / 225.2g) = 0.02944moles Zn²⁺

<em>Moles K₂CO₃ = Moles CO₃²⁻:</em>

0.100L * (0.60mol/L) = 0.060 moles CO₃²⁻

Moles CO₃²⁻ in excess: 0.0600moles CO₃²⁻ - 0.02944moles =

0.03056moles CO₃²⁻ / 0.100L = 0.3056M = [CO₃²⁻]

Replacing in Ksp expression:

1.46x10⁻¹⁰ = [Zn²⁺] [0.3056M]

<h3>[Zn²⁺] = 4.78x10⁻¹⁰M</h3>

4 0
3 years ago
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