Answer:

Explanation:
In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case
) and the anion is the atom at the right of the name (in this case
). With this in mind, the <u>formula would be</u>
.
Now, if we used <u>metallic copper</u> we have to put in the reaction only the <u>copper atom symbol</u>
. So, we have as reagents:

The question now is: <u>What would be the products?</u> To answer this, we have to remember <u>"single displacement reactions"</u>. With a general reaction:

With this in mind, the reaction would be:

I hope it helps!
Answer:
Hence, the wavelength of the photon associated is 1282 nm.
Explanation:
The answer is the 3rd choice