Answer:
![\Delta s = 0.8708\,\frac{kJ}{kg\cdot K}](https://tex.z-dn.net/?f=%5CDelta%20s%20%3D%200.8708%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20K%7D)
Explanation:
The adiabatic throttling process is modelled after the First Law of Thermodynamics:
![m\cdot (h_{in} - h_{out}) = 0](https://tex.z-dn.net/?f=m%5Ccdot%20%28h_%7Bin%7D%20-%20h_%7Bout%7D%29%20%3D%200)
![h_{in} = h_{out}](https://tex.z-dn.net/?f=h_%7Bin%7D%20%3D%20h_%7Bout%7D)
Properties of water at inlet and outlet are obtained from steam tables:
State 1 - Inlet (Liquid-Vapor Mixture)
![P = 1500\,kPa](https://tex.z-dn.net/?f=P%20%3D%201500%5C%2CkPa)
![T = 198.29\,^{\textdegree}C](https://tex.z-dn.net/?f=T%20%3D%20198.29%5C%2C%5E%7B%5Ctextdegree%7DC)
![h = 2726.9\,\frac{kJ}{kg}](https://tex.z-dn.net/?f=h%20%3D%202726.9%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D)
![s = 6.3068\,\frac{kJ}{kg\cdot K}](https://tex.z-dn.net/?f=s%20%3D%206.3068%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20K%7D)
![x = 0.967](https://tex.z-dn.net/?f=x%20%3D%200.967)
State 2 - Outlet (Superheated Vapor)
![P = 200\,kPa](https://tex.z-dn.net/?f=P%20%3D%20200%5C%2CkPa)
![T = 130\,^{\textdegree}C](https://tex.z-dn.net/?f=T%20%3D%20130%5C%2C%5E%7B%5Ctextdegree%7DC)
![h = 2726.9\,\frac{kJ}{kg}](https://tex.z-dn.net/?f=h%20%3D%202726.9%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D)
![s = 7.1776\,\frac{kJ}{kg\cdot K}](https://tex.z-dn.net/?f=s%20%3D%207.1776%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20K%7D)
The change of entropy of the steam is derived of the Second Law of Thermodynamics:
![\Delta s = 7.1776\,\frac{kJ}{kg\cdot K} - 6.3068\, \frac{kJ}{kg\cdot K}](https://tex.z-dn.net/?f=%5CDelta%20s%20%3D%207.1776%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20K%7D%20-%206.3068%5C%2C%20%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20K%7D)
![\Delta s = 0.8708\,\frac{kJ}{kg\cdot K}](https://tex.z-dn.net/?f=%5CDelta%20s%20%3D%200.8708%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20K%7D)
Answer:
C = 292 Mbps
Explanation:
Given:
- Signal Transmitted Power P = 250mW
- The noise in channel N = 10 uW
- The signal bandwidth W = 20 MHz
Find:
what is the maximum capacity of the channel?
Solution:
-The capacity of the channel is given by Shannon's Formula:
C = W*log_2 ( 1 + P/N)
- Plug the values in:
C = (20*10^6)*log_2 ( 1 + 250*10^-3/10)
C = (20*10^6)*log_2 (25001)
C = (20*10^6)*14.6096
C = 292 Mbps
Answer:
it is reducely very iloretable chance for a software engineer to give an end to this question
A. Email your teacher right away. It would be the safest option.
Answer:
14.36((14MPa) approximately
Explanation:
In this question, we are asked to calculate the stress tightened in a bolt to a stress of 69MPa.
Please check attachment for complete solution and step by step explanation