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pickupchik [31]
3 years ago
15

Two parts are to be assembled in a way that if one part fails, the entire assembly fails. Each of the parts have undergone exten

sive individual analysis and you are provided with statistics on the stresses that are expected. Specifically, you are provided with the mean and standard deviation of the stress, and the yield stress of the material for each part. Failure of a part will be defined as a part experiencing stress exceeding the yield stress. What is the probability that the assembly fails? (Hint: Use Table A-10 in the textbook to find the probability of failure for each part.)
Part #1: σnom = 260 MP a, U (σ) = 25 MP a, σyield = 310 MPa

Part #2: σnom = 475 MP a, U (σ) = 5 MP a, σyield = 490 MPa

Engineering
1 answer:
e-lub [12.9K]3 years ago
5 0

Answer:

attached below

Explanation:

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What is the purpose of having a ventilation system on board a motorized vessel?.
chubhunter [2.5K]

The purpose of having a ventilation system on board a motorized vessel is : To remove flammable gas from a vessel to avoid explosions.

<h3>Meaning of ventilation system</h3>

A ventilation system can be defined as a system that allows for removal of gases from a vessel to the atmosphere.

A Ventilation system is very important in every motorized vessel because they help to eliminate or remove flammable gases that are dangerous and are liable to explode when held in a large amount in the engine.

In conclusion, The purpose of having a ventilation system on board a motorized vessel is to remove flammable gas from a vessel their by avoiding explosions.

Learn more about Ventilation System: brainly.com/question/1687520

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4 0
2 years ago
A mass of 5 kg of saturated liquid-vapor mixture of water is contained in a piston-cylinder device at 125 kPa. Initially, 2 kg o
arlik [135]
A because it is the best one
5 0
3 years ago
Three-dimensional measuring references all of these EXCEPT:
cricket20 [7]
Except the Table of Contents
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When moving cylinders always remove and make
Karolina [17]

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5 0
3 years ago
Steam at 40 bar and 500o C enters the first-stage turbine with a volumetric flow rate of 90 m3 /min. Steam exits the turbine at
a_sh-v [17]

Answer:

(a) 62460 kg/hr

(b) 17,572.95 kW

(c) 3,814.57 kW

Explanation:

Volumetric flow rate, G = 30 m³ / 1 min => 90 / 60 => 1.5

Calculate for h₁ , h₂ , h₃

h₁ is h at P = 40 bar, 500°C => 3445.84 KJ/Kg

Specific volume steam, ц = 0.086441 m³kg⁻¹

h₂ is h at P = 20 bar, 400°C => 3248.23 KJ/Kg

h₃ is h at P = 20 bar, 500°C => 3468.09 KJ/Kg

h₄ is hg at P = 0.6 bar from saturated water table => 2652.85 KJ/Kg

a)

Mass flow rate of the steam, m = G / ц

m = 1.5 / 0.086441

m = 17.35 kg/s

mass per hour is m = 62460 kg/hr

b)

Total Power produced by two stages

= m (h₁ - h₂) + m (h₃ - h₁)

= m [(3445.84 - 3248.23) + (3468.09 - 2652.85)]

= m [ 197.61 + 815.24 ]

= 17.35 [1012.85]

= 17,572.95 kW

c)

Rate of heat transfer to the steam through reheater

= m (h₃ - h₂)

= 17.35 x (3468.09 - 3248.23)

= 17.35 x 219.86

= 3,814.57 kW

8 0
3 years ago
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