Two parts are to be assembled in a way that if one part fails, the entire assembly fails. Each of the parts have undergone exten
sive individual analysis and you are provided with statistics on the stresses that are expected. Specifically, you are provided with the mean and standard deviation of the stress, and the yield stress of the material for each part. Failure of a part will be defined as a part experiencing stress exceeding the yield stress. What is the probability that the assembly fails? (Hint: Use Table A-10 in the textbook to find the probability of failure for each part.)
Part #1: σnom = 260 MP a, U (σ) = 25 MP a, σyield = 310 MPa
Part #2: σnom = 475 MP a, U (σ) = 5 MP a, σyield = 490 MPa
Part #1: σnom = 260 MP a, U (σ) = 25 MP a, σyield = 310 MPa
Part #2: σnom = 475 MP a, U (σ) = 5 MP a, σyield = 490 MPa
1 answer:
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Answer:
98,614.82 W/m²
Explanation:
Where;
Q = the amount of heat loss from the pipe
h = the heat transfer coefficient of the pipe = 50 W/m².K
T₁ = the ambient temperature of the pipe = 30⁰C
T₂ = the outside temperature of the pipe = 100⁰C
L= the length of pipe
r₁ = inner radius of the pipe = 20mm
r₂ = outer radius of the pipe = 25mm
To determine the amount of heat loss from the pipe per unit length
From the equation above
= 98,614.82 W/m²
Answer:
28.6 kg
Explanation:
The final weight can be calculated from the mixing data and formulae which is given as follows:
cement content =
Computing the parameters and checking the tables gives 28.6 kg.
This is the answer for the question
