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Lerok [7]
3 years ago
11

X+3=2x=??No spamming​

Engineering
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

x+3=2

x=2-3꧁

꧁꧁꧂꧂꧂꧂

x=-1

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Assume that the water temperature is 10°C and the depth of the settling tank is 3.0 m (9.80 ft). Calculate the theoretical settl
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See attached file

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Implement a function called myFilter that does the following: Takes a sequence of integers with values from 0 to 100 Remove all
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Answer:

using System;

using System.Collections.Generic;

using System.Linq;

public class Problem1 {

public static IEnumerable < int > myFilter(IEnumerable < int > input) {

return input.Where((val, index) => {

//First remove all multiples of 6 less than 42

return !(val % 6 == 0 && val < 42);

}).Select((val, index) => {

//Then square each number

return val * val;

}).Where((val, index) => {

// Finally, remove any resulting integer that is odd

return !(val % 1 == 0);

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}

public static void Main(string[] args) {

Random rnd = new Random(5);

//Takes a sequence of integers with values from 0 to 100

var listForProblem = Enumerable.Range(1, 100).Select(i => rnd.Next() % 101);

var answer = Problem1.myFilter(listForProblem);

foreach(int i in answer) {

Console.WriteLine(i);

}

}

}

Explanation:

The Problem 1 solution is explanatory enough.

Your problem 2 question is lacking details. However, i have written a code that sorts it.

6 0
3 years ago
What is rainfall intensity
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3 0
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Read 2 more answers
When selecting the appropriate gear for intended direction of travel, automatic transmission equipped vehicles should be placed
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3 years ago
1. The equilibrium number of vacancies in Ni at 1123 K is 4.7x1022m-3. The atomic weight and density of Ni at 1123 K are 58.69 g
Ahat [919]

Answer:

vacancy formation energy of Ni is 1.400 eV

Explanation:

given data

number of vacancies in Ni = 4.7 x 10^{22}  m^{-3}

atomic weight = 58.69 g/mol

density = 8.8 g/cm³  

solution

we get here N that is

N  = \frac{N_A \times \rho}{A}   ...........1

N = \frac{6.023\times 10^{23} \times 8.8 \times 10^6}{58.69}

N = 9.030 \times 10^{28}  

and here no of vacancy will be

Nv = N \times e^{\frac{-Qv}{kT}}  .................2

put here value

4.7 \times 10^{22} = 9.030 \times 10^28 \times e^{\frac{-Qv}{8.62\times 10^{-5}\times 1123}}  

10^{-7} \times 5.20487 = e^{\frac{-Qv}{0.0968}}

take ln both side

ln (10^{-7} \times 5.20487 ) = ln (e^{\frac{-Qv}{0.0968}})

-14.468 = \frac{-Qv}{0.0968}  

Qv = 1.400 eV

so vacancy formation energy of Ni is 1.400 eV

3 0
3 years ago
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