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The number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles
From the question,
We are to determine the number of moles of silver, Ag, that are present in 7.54 × 10²³ atoms of silver
From the formula
Avogadro's constant = 6.022 × 10²³ atoms mol⁻¹
and
From the given information
Number of silver atoms = 7.54 × 10²³ atoms
Putting the parameters into the formula, we get
Number of moles of silver present =
Number of moles of silver present = 1.2520757 moles
Number of moles of silver present ≅ 1.25 moles
Hence, the number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles
Learn more on calculating number of moles here: brainly.com/question/15839520
Answer:
Explanation:
Hello,
In this case, given the percent ionization and the concentration of the acid, one computes the concentration of hydrogen ions as follows:
Therefore the Ka is computed by using the equilibrium expression:
And the pH:
Regards.