CH4 + 2O2→CO2 + 2H2O
Explanation:
CH4 + O2→CO2 + H2O
First look at the C atoms. At first glance they are balanced with 1 C on each side.
Now look at the H atoms. They are not balanced. There are 4 H atoms on the left side and 2 H atoms on the right. Place a coefficient of 2 in front of the H2O. We now have 4 H atoms on both sides.
CH4 + O2→CO2 + 2H2O
Now look at the O atoms. They are not balanced. There are 2 O atoms on the left side and 4 on the right. Place a coefficient of 2 in front of the O2. We now have 4 O atoms on both sides.
CH4 + 2O2→CO2 + 2H2O
The equation is now balanced. Each side has 1 C atom, 4 H atoms, and 4 O atoms.
Answer: A degenerate pressure will generate a large force to repel further compression.
Explanation: In the production of new stars from the core of old dying white dwarf stars, the inner parts of the star will experience contraction with the release of heat , as they contract, their atoms will be squeezed such that their electrons start to overlap, and because of the Pauli's exclusive principle which states that no two electrons can occupy same space, the electrons will begin to repel each other and an opposing pressure called degenerate pressure will create a force so that the electrons cannot continually be crushed or overlap. With the limit of contraction, the outer parts of the star will expand and be repelled releasing the old stars called nebula and creating space for the inner new stars to form.
Answer:
P(H₂) = 0.8533 atm
Explanation:
n(CO) = 0.220 mole
n(H₂) = 0.350 mole
n(He) = 0.640 mole
_______________
∑ n = 1.210 moles
mole fraction => X(H₂) = 0.350/1.210 = 0.2892
Dalton's Law of Partial Pressures => P(H₂) = X(H₂)·P(ttl) = 0.2892(2.95 atm) = 0.8533 atm
Answer:decreases
Explanation it takes energy from it to change
Correct If not right, but, In low temperatures intermolecular forces also increase, since molecules move more slowly, similar to what would occur in a liquid state. Just remember that ideal gas behavior is most closely approximated in conditions that favor gas formation in the first place—heat and low pressure. me.
