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jarptica [38.1K]
3 years ago
13

During fusion

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
5 0
The 1st one

thank me later
Veronika [31]3 years ago
3 0

Answer:

A

Explanation:

uranium atoms are fused together

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For the separation of components of a mixture, we are following different methods. What is the condition in which the process of
soldier1979 [14.2K]

Answer:

The mixture 1/ must be homogeneous where there is one or more dissolved salts; 2/ should only contain one liquid component.

Explanation:

This method drives off the liquid components from the solid components. The process typically involves heating the mixture until no more liquid remains. Prior to using this method, the mixture should only contain one liquid component, unless it is not important to isolate the liquid components. This is because all liquid components will evaporate over time. This method is suitable to separate a soluble solid from a liquid.

Note : In many parts of the world, table salt is obtained from the evaporation of sea water. The heat for the process comes from the sun.

...

Hope this answer can help you. Have a nice day!

4 0
3 years ago
If a chlorine atom gains or loses a valence electron, it becomes a charged particle called a/an ___ A. Flourine B. Chloride atom
Triss [41]

option c is the answer

ROCK ON DUDE

8 0
3 years ago
Read 2 more answers
What is the pressure of 0.60 moles of a gas if its volume is 10.0 liters at 35.0°C
eduard

Answer: 1.52 atm

Explanation:

Given that:

Volume of gas V = 10.0L

Temperature T = 35.0°C

Convert Celsius to Kelvin

(35.0°C + 273 = 308K)

Pressure P = ?

Number of moles = 0.6 moles

Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 10.0L = 0.6 moles x (0.0821 atm L K-1 mol-1 x 308K)

p x 10.0L = 15.17 atm L

p = 15.17 atm L / 10.0L

p = 1.517 atm (round to the nearest hundredth as 1.52 atm)

Thus, the pressure of the gas is 1.52 atm

3 0
3 years ago
Gold has density of 19.3 g/cm3; how many grams of gold are in a 16.0 cm3 gold bar?
Andre45 [30]
To determine the mass of gold, we simply multiply the density and volume. Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We do as follows:

mass = density x volume
mass = 19.3 g/cm^3 ( 16.0 cm^3 )
mass = 308.8 g
6 0
3 years ago
How many micrograms (ug) are in 3.4 x 10^-5 ounces (oz)
marysya [2.9K]

Answer:

964ug

Explanation:

The problem here involves converting from one unit to another.

 We are to convert from ounces to micrograms.

                                    1ug  = 1 x 10⁻⁶g

                                    1oz  = 28.35g

       

So we first convert to grams from oz then take to ug:

 Solving:

                    1oz  = 28.35g

             3.4 x 10⁻⁵oz  will then give  3.4 x 10⁻⁵ x 28.35 = 9.64  x 10⁻⁴g

So;

                    1 x 10⁻⁶g    = 1ug

          9.64  x 10⁻⁴g will give \frac{9.64 x 10^{-4} }{1 x 10^{-6} }      = 9.64 x 10²ug or 964ug

8 0
2 years ago
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