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4 years ago

A compound contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen (by mass). calculate the empirical formula.

Chemistry

1 answer:

Eva8 [605]4 years ago

3 0

C:H:O = 40/12 : 6,7/1 : 53,3/16 = 3,33 : 6,7 : 3,33 ≈ 1 : 2 : 1

CH₂O

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List these distance units in order from smallest to largest: nm,m,km,dm

docker41 [41]

Answer:

nm, dm, km, m

Explanation:

1 nanometer = 1e-12 (0.000000000001) kilometers

1 decimeter = 1e-4 (0.0001) kilometers

1 kilometer = 1 kilometer

Regardless of whether 'm' stands for mile or meter, it's still larger than all of these being approx. 1.61 and 1e-3 (0.001) kilometers respectively.

in the future, please provide the exact units.

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nanometers, decimeters, kilometers, meters

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3 years ago

Which of the following statements is/are true of oxides? 1. A basic oxide is an oxide that reacts with bases. 2. An acidic oxide

lapo4ka [179]

Answer:

Correct option: <em>3</em>

Explanation:

A basic oxide is an oxide that reacts with water to give base or reacts with acid to form salt

eg:

Sodium oxide reacts with water to produce sodium hydroxide.

Magnesium oxide gives magnesium chloride on reaction with hydrochloric acid

An acidic oxide is an oxide that reacts with water to give acid and reacts with base to give salt.

eg: Carbon dioxide gives carbonic acid on reaction with water .

Sulfur dioxide gives sulfites when reacs reacts with bases.

An amphoteric oxide is an oxide which reacts with base as well acid and it shows because metal have multiple oxidation state and they can form oxide as well hydroxide

$eg: Al_2O_3$

4 0

3 years ago

The general form AB àA + B represents which type of reaction?

Monica [59]

Answer:

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7 0

2 years ago

Negative ions form when atoms _______ valence electrons.

zhenek [66]

Answer:

Negatively charged ions are called anions, and an anion is formed when an atom gains an electron. Thus, the atom has an extra charge of electrons,

Explanation:

so it becomes negatively charged.

3 0

2 years ago

Read 2 more answers

The decomposition of ethylene oxide(CH₂)₂O(g) → CH₄(g) + CO(g)is a first order reaction with a half-life of 58.0 min at 652 K. T

olga55 [171]

Answer:

Half-life at 629K = 252.4min

Explanation:

Using Arrhenius equation:

$ln\frac{K_1}{K_2} = \frac{Ea}{R} (\frac{1}{T_2} -\frac{1}{T_1})$

And as Half-life in a first order reaction is:

$t_{1/2}=\frac{ln2}{K}$

We can convert the half-life of 58.0min to know K₁ adn replacing in Arrhenius equation find half-life at 629K:

$58.0min=\frac{ln2}{K}$

K = 0.01195min⁻¹ = K₁

$ln\frac{0.01195min^{-1}}{K_2} = \frac{218kJ/mol}{8.314x10^{-3}kJ/molK} (\frac{1}{629K} -\frac{1}{652K})$

$ln\frac{0.01195min^{-1}}{K_2} =1.47$

$\frac{0.01195min^{-1}}{K_2} =4.35$

K₂ = 2.75x10⁻³ min⁻¹

And, replacing again in Half-life expression:

$t_{1/2}=\frac{ln2}{2.75x10^{-3}min^{-1}}$

5 0

3 years ago