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Bezzdna [24]
3 years ago
5

A compound contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen (by mass). calculate the empirical formula.

Chemistry
1 answer:
Eva8 [605]3 years ago
3 0
C:H:O = 40/12 : 6,7/1 : 53,3/16 = 3,33 : 6,7 : 3,33 ≈ 1 : 2 : 1

CH₂O
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Determine the value of the equilibrium constant, Kgoal, for the reaction C(s)+12O2(g)+H2(g)⇌12CH3OH(g)+12CO(g), Kgoal=? by makin
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1.71x10²⁷

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C(s) + 1/2O₂(g) +<u> 1/2CO₂(g) </u>+<u> 3/2H₂(g</u>) ⇌ 1/2CH₃OH(g) + <u>1/2H₂O(g)</u> + <u>CO(g)</u>

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+1/2 (2):

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Answer:

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:)

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