1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ulleksa [173]
2 years ago
6

A compound of mercury and oxygen is heated in order to decompose the compound. A 4.08 grams sample of mercury oxide upon heating

gives off oxygen gas. After heating the mass of mercury metal left behind was 3.78 grams. Calculate the empirical formula of the compound
My and: 1 O2 to 2 Hg ratio but I don't know if it's correct and if so if I should write it as
2HgO ----> 2Hg + O2 or just 2Hg + O2
Please someone who understands help.
Chemistry
1 answer:
arlik [135]2 years ago
7 0

Answer:

HgO (empirical formula)

Explanation:

4.08 - 3.78 = 0.3g (oxygen)

(\frac{4.08}{201})   \:  \:  \:  (\frac{0.3}{16} )

0.02 : 0.02

0.02/0.02 : 0.02/0.02

1 : 1 (ratio)

HgO ( empirical formula)

2HgO ----> 2Hg + O2 ( your equation correct)

You might be interested in
An "empty" container is not really empty if it contains air. How may moles of nitrogen are in an "empty" two-liter cola bottle a
Lisa [10]

Answer:

1. 0.0637 moles of nitrogen.

2. The partial pressure of oxygen is 0.21 atm.  

Explanation:

1. If we assume ideal behaviour, we can use the Law of ideal gases to find the moles of nitrogen, considering that air composition is mainly nitrogen (78%), oxygen (21%) and argon (1%):  

V_{N_2}=V_{T}\times 0.78=2L \times 0.78 =1.56 L\\PV=nRT\\n_{N_2}=\frac{PV}{RT}=\frac{1 atm\times 1.56 L}{0.0821\frac{atmL}{molK}\times 298 K}\\n_{N_2}= 0.0637 mol

2. Now, in order to find he partial pressure of oxygen we need to find the total moles of air, and then the moles of oxygen. Then, we use these results to determine the molar fraction of oxygen, to multiply it with total pressure and get the partial pressure of oxygen as follows:

n_{total}=\frac{1 atm \times 2L}{0.0821 \frac{atmL}{molK}298K}=0.0817 mol

V_{O_2}=2L \times 0.21 = 0.42 L\\n_{O_2}=\frac {1atm \times 0.42 L}{0.0821 \frac{atm L}{mol K}298 K}=0.0172 mol\\X_{O_2}=\frac{n_{O_2}}{n_{total}}=\frac{0.0172 mol}{0.0817 mol}= 0.21

P_{O_2}=X_{O_2} \times P = 1 atm \times 0.21 = 0.21 atm

As you see, the molar fraction and volume fraction are the same because of the assumption of ideal behaviour.  

3 0
3 years ago
The very common mineral shown in this photograph is commonly a pink- to cream-colored mineral with wavy, light-colored lines. it
musickatia [10]
The very common mineral shown in the figure that is referred in this problem that is commonly a pink- to cream-colored mineral with wavy, light-colored lines and does not effervesce would be feldspar. It make up about 41 percent weight of the Earth's crust. It is a group of rocks that contains tectosilicate compounds.
8 0
3 years ago
Please Help Me!!!
sergejj [24]

Answer:

The products are carbon dioxide and water

Explanation:

Step 1: Data given

Combustion = a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve  O2  as one reactant.

Step 2: The complete combustion of C3H7OH:

For the combustion of 1-propanol, we need O2.

The products of this combustion are CO2 and H2O.

C3H7OH + O2→ CO2 + H2O

On the left side we have 3x C (in c3H7OH), on the right side we have 1x C (in CO2). To balance the amount of C, we have to multiply CO2 on the right side by 3

C3H7OH + O2→ 3CO2 + H2O

On the left side we have 8x H (in C3H7OH) and 2x on the right side (in H2O). To balance the amount of H, we have to multiply H2O, on the right side by 4.

C3H7OH + O2→ 3CO2 + 4H2O

On the left side we have 3x O (1x in C3H7OH and 2x in O2), on the right side we have 10x O (6x in CO2 and 4x in H2O).

To balance the amount of O on both sides, we have to multiply C3H7OH by 2, multiply O2 by 9. Then we have to multiply 3CO2 by 2 and 4H2O by 2. Now the equation is balanced.

2C3H7OH + 9O2→ 6CO2 + 8H2O

For 2 moles propanol, we need 9 moles of O2 to produce 6 moles of CO2 and 8 moles Of H2O

The products are carbon dioxide and water

7 0
3 years ago
What is the one variable that is changed in the experimental group called? the placebo the independent variable the control grou
BlackZzzverrR [31]

Answer:

the independant variable

Explanation:

4 0
3 years ago
Which clouds are often associated with thunder and lightning?
FrozenT [24]
Cumulonimbus clouds, of course!. These clouds are known to carry rain, hail, and thunder. Bigger versions are known as supercells, deadly storms that can spew out tons of rain, hail, wind, and even tornadoes!
6 0
3 years ago
Read 2 more answers
Other questions:
  • Which type of orbitals overlap to form the sigma bond between C and N in H−C≡N:? Which type of orbitals overlap to form the sigm
    9·1 answer
  • An aqueous solution containing 7.96 g7.96 g of lead(II) nitrate is added to an aqueous solution containing 6.82 g6.82 g of potas
    6·1 answer
  • 3) (4.5 x 10-14) x (5.2 x 103) = ?
    8·2 answers
  • The following reaction was carried out in a 3.00 L reaction vessel at 1100 K:
    11·1 answer
  • 1. What makes a plant vacuole different from an animal vacuole? |
    14·1 answer
  • 200 feet in 30 seconds is what speed?
    15·2 answers
  • SOME HELP WOULD BE NICE!!! PLEASEEE
    11·1 answer
  • Identify 3 characteristics that would be taken into consideration when evaluating any proposed site for a national repository of
    9·1 answer
  • State at least three different properties of metallic compounds?
    8·2 answers
  • The distance between two successive peaks is called
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!