Answer: The molar mass of the given compound is 
Explanation:
In molecular formula of 
there are two chlorine atoms and one calcium atom.
The atomic mass of the calcium = 40.07 g/mol
The atomic mass of chlorine = 35.5 g/mol
Molar mass of the guven compound is :
The molar mass of the given compound is
Equation: 2H₂ + O₂ → 2H₂O
Now, Given mass of Oxygen = 192 g
Molar mass of Oxygen = 16 g/mol
No. of moles in Oxygen = 16/192 = 0.0833
Now, for every mole of Oxygen, 2 mole of Hydrogen will form,
so, Number of moles of Hydrogen = 0.0833 * 2 = 0.167
Given mass = Number of Moles * Molar mass
Given mass = 0.167 * 2
m = 0.33 g
In short, Your Answer would be: 0.33 g
Hope this helps!
The value of pka for 
in an aqueous solution is 9.2.
<h3>What is Kb?</h3>
Kb denotes the base dissociation constant.
pKa + pKb =14 at 25 degree celcius.
pKa + 4.8 =14
pKa = 9.2
pKb is the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.
It is used to determine the strength of a base or alkaline solution.
The value of pka for in an aqueous solution is 9.2.
Learn more about pka here:
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<span>An enzyme is a protein, and proteins need certain temperatures to function optimally, or even function. Temperature may unfold the protein and may stop its functioning, or it may fold the protein into the correct formation to function. But by the way your question asks, EXCESS heat would denature the enzyme and cease function.</span>
Answer:
7. A) I, II
; 8. D) 2.34e9 kJ
Step-by-step explanation:
7. Combustion of ethanol
I. The negative sign for ΔH shows that the reaction is exothermic.
II. The enthalpy change would be different if gaseous water were produced.
That's because it takes energy to convert liquid water to gaseous water, and this energy is included in the value of ΔH.
III. The reaction is a redox reaction, because
- Oxygen is reacting with a compound
- The oxidation number of C increases
- The oxidation number of O decreases.
IV. The products of the reaction occupy a smaller volume than the reactants, because 3 mol of gaseous reactant are forming 2 mol of gaseous product.
Therefore, only I and II are correct.
7. Hindenburg
Data:
V = 2.00 × 10⁸ L
p = 1.00 atm
T = 25.1 °C
ΔH = -286 kJ·mol⁻¹
Calculations:
(a) Convert temperature to kelvins
T = (25.1 + 273.15) K = 298.25 K
(b) Moles of hydrogen
Use the <em>Ideal Gas Law</em>:
pV = nRT
n = (pV)/(RT)
n = (1.00 × 2.00 × 10⁸)/(0.082 06 × 298.25) = 8.172 × 10⁶ mol
(c) Heat evolved
q = nΔH = 8.172 × 10⁶ × (-286) = -2.34 × 10⁹ kJ
The hydrogen in the Hindenburg released 2.34e9 kJ
.
