Answer:
12 moles of cesium xenon heptafluoride
Explanation:
The reaction of cesium fluoride with xenon hexafluoride is CeF + XeF6 -> CeXeF7 and the reaction is balanced as written. So the mole ratio is 1:1:1. We are given 12 moles of CeF and 14 moles of XeF6 are reacting, but after the 12 moles of CeF react completely, the reaction will stop as we have run out of one of our reactants. So only 12 moles of CeXeF7 will be produced.
Answer:
everyone would die
Explanation:
if we did not know about it we would not do anything about it
Answer:
(1) 0.0016 mol/L
Explanation:
Let the concentration of alcohol after 3.5 hours be y M
The reaction follows a first-order
Rate = ky^0 = change in concentration/time
k = 6.4×10^-5 mol/L.min
Initial concentration = 0.015 M
Concentration after 3.5 hours = y M
Time = 3.5 hours = 3.5×60 = 210 min
6.4×10^-5y^0 = 0.015-y/210
y^0 = 1
0.015-y = 6.4×10^-5 × 210
0.015-y = 0.01344
y = 0.015 - 0.01344 = 0.00156 = 0.0016 mol/L (to 4 decimal places)
The reasonable ground-state electron configuration is: 1s2 2s2 2p6 3s2 3p6 4s2 4d8
The simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens is 1 O atom/ 2 H atoms.
Sucrose is a diasaccharide having the formula; C12H22O11.
This implies that there are twenty two atoms of hydrogen and eleven atoms of oxygen in a molecule of sucrose.
This gives a ratio of 2 hydrogen atoms to one oxygen atom. Therefore, the simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens is 1 O atom/ 2 H atoms.
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