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Alex73 [517]
4 years ago
6

Considering the temperature vs. time graph below, how does the temperature at the beginning of a change of state

Chemistry
2 answers:
masya89 [10]4 years ago
8 0

Answer:

The temperature is always lower

Explanation:

Cloud [144]4 years ago
6 0

Answer:

The temperature is always lower.

Explanation:

The temperature is always lower at the end of the state as compared to beginning of the state. We can see in the given data, the temperature is higher at the beginning i. e. 140 degree Celsius but with the passage of time, the temperature of a state decreases constantly  and the temperature at the end is lower i. e. 20 degree Celsius. So we can conclude that the temperature is always lower.

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ra1l [238]

Answer:

Granite

Explanation:

The specific heat capacity of a substance, which is denoted by "c", is the amount of heat required to raise the temperature of a particular mass of that substance by 1°C. It is calculated as follows:

c = Q ÷ m∆T

Where;

c = specific heat capacity

Q = amount of heat (J)

m = mass of substance

∆T = change in temperature.

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3 0
3 years ago
Anyone? Please help
snow_tiger [21]

Answer:

The limiting reacting is O2

Explanation:

Step 1: data given

Number of moles O2 = 21 moles

Number of moles C6H6O = 4.0 moles

Step 2: The balanced equation

C6H6O + 7O2 → 6CO2 + 3H2O

Step 3: Calculate the limiting reactant

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed (21 moles).

C6H6O is in excess.

For 7 moles O2 we need 1 mol C6H6O

For 21 moles O2 we'll need 21/7 = 3 moles C6H6O

There will remain 4.0 - 3.0 = 1 mol C6H6O

Step 4: calculate products

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2

For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O

The limiting reacting is O2

7 0
4 years ago
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