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elena-14-01-66 [18.8K]
3 years ago
6

NEED HELP ASAP PLEASE!

Chemistry
1 answer:
Serjik [45]3 years ago
6 0

Answer:

20 moles of o2

5 moles=4moles

?moles=16moles

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22 Determine the molar mass of an unknown gas that has a volume of 72.5 mL at a temperature of 68C, and a pressure of 0.980 atm
jekas [21]

Answer:

81.5g/mol

Explanation:

Molar mass is the ratio between mass of a substance (In this case, 0.207g) and moles presents in this mass.

To solve this question we must find the moles of the gas in order to obtain the molar mass using:

PV = nRT

PV / RT = n

<em>Where P is pressure = 0.980atm</em>

<em>V is volume in Liters = 0.0725L</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 68°C + 273.15 = 341.15K</em>

<em />

0.980atm*0.0725L / 0.082atmL/molK*341.15K = n

2.54x10⁻³ moles = n

Thus, the molar mass of the gas is:

0.207g / 2.54x10⁻³ moles

<h3>81.5g/mol</h3>
5 0
3 years ago
6.
omeli [17]

Answer:

gains two electron!

Explanation:

When a barium atom forms its most common ion, it gains two electron!

7 0
3 years ago
A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 4
yan [13]

7.91 g/ml is the density of the iron piece of 28.5 gms.

Explanation:

The density of a substance is defined as the volume it occupies.  It tells the matter present in a substance.

The density is mass per unit volume and is denoted by p.

The formula for density is given by:

density (p) = \frac{mass}{volume}

Data given is :

mass= 28.5 grams

V1 = 45.5 ml

V2= 49.1 ml

The initial volume of water was 45.5 ml, when iron piece of 28.5 grams was added the final volume was 49.1 ml.

Putting the values in the equation of density

p = \frac{28.5}{49.1-45.5}

p = 7.91 g/ml

Since iron is a dense material it will occupy less volume

4 0
3 years ago
If the visible light spectrum is from 400 to 700 nm, would light with an energy of 2.79 x 10^-19 J be visible with the naked eye
sladkih [1.3K]

Answer:

713 nm. It is not visible with the naked eye.

Explanation:

Step 1: Given data

  • Energy of light (E): 2.79 × 10⁻¹⁹ J
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s
  • Speed of light (c): 3.00 × 10⁸ m/s
  • Wavelength (λ): ?

Step 2: Calculate the wavelength of the light

We will use the Planck-Einstein equation.

E = h × c / λ

λ = h × c / E

λ = 6.63 × 10⁻³⁴ J.s × 3.00 × 10⁸ m/s / 2.79 × 10⁻¹⁹ J

λ = 7.13 × 10⁻⁷ m

Step 3: Convert "λ" to nm

We will use the relationship 1 m = 10⁹ nm.

7.13 × 10⁻⁷ m × (10⁹ nm/1 m) = 713 nm

This light is not in the 400-700 nm interval so it is not visible with the naked eye.

5 0
3 years ago
A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure
Ostrovityanka [42]

The volume did not change, it remained at 20 ml

<h3>Further explanation</h3>

Given

20 ml a sample gas at STP(273 K, 1 atm)

T₂=546 K

P₂=2 atm

Required

The volume

Solution

Combined gas Law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

\tt \dfrac{1\times 20}{273}=\dfrac{2\times V_2}{546}\\\\V_2=\dfrac{1\times 20\times 546}{273\times 2}\\\\V_2=20~ml

The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)

5 0
3 years ago
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