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3 years ago

Anyone know how to do this work plz

Mathematics

1 answer:

Bingel [31]3 years ago

4 0

I need help on this to sad

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I will make brainliest to first person!!!!!!!!

sammy [17]

11 = 0.65
12 = ?
13 = 20%

7 0

3 years ago

Read 2 more answers

What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Nadya [2.5K]

x-intercepts are found by setting y=0
$y=2x^2-8x-10\rightarrow0=2x^2-8x-10$
factor out a 2 $0=2(x^2-4x-5)\rightarrow0=x^2-4x-5$
 $0=(x-5)(x+1)$ roots should be x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)

y-intercepts are found by setting x=0
$y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10$
$\rightarrow y=0-0-10=-10$
therefore, y-intercept is (0,-10)

4 0

3 years ago

What are the 2 shapes

uysha [10]

A stop sign shape i think

6 0

4 years ago

A.2.00 b. 2.50 c 5.25 d 10.50

klemol [59]

Answer:

the picture is blurry

Step-by-step explanation:

<h2>can. you give me another picture? plz</h2>

5 0

3 years ago

An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h

LenKa [72]

The pool can hold 65.84 ft³ of water

Explanation:

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

$\frac{11}{1+\sqrt{2} } = a^2$

a² = $\frac{11}{2.42}$

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = $2(1+\sqrt{2} ) X (a)^2 X h$

$V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3$

Therefore, the pool can hold 65.84 ft³ of water

8 0

3 years ago

Anyone know how to do this work plz​

Anyone know how to do this work plz