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2 years ago

Why do airbags fill evenly with gases.

Chemistry

1 answer:

wel2 years ago

8 0

Answer:

The signal from the deceleration sensor ignites the gas-generator mixture by an electrical impulse, creating the high-temperature condition necessary for NaN3 to decompose. The nitrogen gas that is generated then fills the airbag.

Explanation:

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Which compounds has more nonbonding electrons? a. butene b. ethane?

Elden [556K]

Ethane is non Bond electron

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2 years ago

A student is asked to convert measurements from grams to kilograms and from kilograms to grams. His answers are shown in bold in

Margaret [11]

Whats the answers shown in bold.

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2 years ago

What is the mass of oxygen in 25.0 grams of potassium permanganate , KMnO4?

Katen [24]

Answer:

10.76 grams

Explanation:

Given that the amount of $KMnO_4$ is 25.0 grams.

Mass of 1 mole of $KMnO_4$ = 158 grams

The number of atoms in 1 mole of $KMnO_4$ is 4.

Mass of oxygen in 1 mole of $KMnO_4$ = 16\times 4 = 68 grams.

Here, 158 grams of $KMnO_4$ has 68 grams of oxygen

So, the amount of oxygen in 1 gram of $KMnO_4$ = 68/158 grams

Therefore, the amount of oxygen in 1 gram of $KMnO_4$ = $\frac {68}{158}\times 25$ grams

=10.76 grams

Hence, 25 grams of $KMnO_4$ has 10.76 grams of oxygen.

3 0

2 years ago

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When you add energy to matter the particles move

snow_tiger [21]

Answer:

Energy added: particles move faster and further apart, and matter expands (state changes from solid to liquid to gas). Energy removed: particles move slower and closer together, and matter contracts (state changes from gas to liquid to solid).

Explanation:

5 0

3 years ago

8. If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A?

lakkis [162]

We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water

From the question we are told

If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A

Generally the equation for the Concentration Volume relationship is mathematically given as

$C1V1=C2V2\\\\Where\\\\C1=10X\\\\C2=1X buffer A\\\\V2=450ml \\\\Therefore\\\\V1=\frac{450*1}{10}\\\\V1=45ml$

Therefore

You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water

For more information on this visit

brainly.com/question/17756498

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2 years ago