The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
Read more about transformation at
brainly.com/question/1548871
#SPJ1
Answer:
|p| = 4
Step-by-step explanation:
|p| = 4 is the only answer that would fit for both scenarios of a player winning or loosing points after their first turn of the game.
To calculate the IQR, we need the radian, which is the middle number of each column, namely (86,82) for each exam.
Above the middle number, we have 5 values. The middle value (of the upper part) is Q3, which is on the third line, or (92,85).
Below the middle number, we also have 5 values. The middle (of the lower half) is Q1, which is on the 9th line (80,78)
The IQR is the difference between Q3 and Q1, namely
(92-80, 85-78) = (12, 7)
Since 12>7, we conclude that the IQR of the mid-term is higher than the final.
Answer:
25 meters
Step-by-step explanation:
Imagine a segment extending vertically down from the left tree to the right tree.
That would make the segment be 25-10, or 15.
Then, we have a right triangle and we can solve for the hypotenuse, which is the length of the rope. (The bottom of the triangle is 20, and the leg is 15.)
We can use the pythag theorem: 15^2+20^2=c^2
c^2=225+400
c^2=625
c=25
Therefore, 25 meters
I hope the helped! If you have any further questions or concerns, please feel free to comment them below!
