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3 years ago

HELP PLS ITS DUE TONIGHTSTEP BY STEP

Mathematics

1 answer:

Natali [406]3 years ago

3 0

Aight so first you need to isolate the y. Simply add 8 to both sides and now you have 1/4y = 33. Now divide both sides by 1/4 (which is the same by multiplying by 4) and you get 132

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A quadrilateral is reflected over the y-axis. Which of the following statements about the coordinates of the image are true?

Nat2105 [25]

If it’s only reflected over the y axis then only the x values change

5 0

3 years ago

HELP ME RN PLEASEEEE<br> [WILL GIVE BRAINLY TO CORRECT AND BEST EXPLAINED ANSWER]

VMariaS [17]

Answer:

$\boxed {\boxed {\sf d= \sqrt{34}}}$

Step-by-step explanation:

We want to find the distance between two points, so the following formula is used.

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Where (x₁, y₁) and (x₂, y₂) are the points we are finding the distance between.

We are given the points (-2, -1) and (3,2). If we match the corresponding value and variable we see that:

x₁= -2
y₁= -1
x₂= 3
y₂= 2

Substitute the values into the formula.

$d= \sqrt {(-2-3)^2+(2--1)^2$

Solve the parentheses.

-2 -3 = -5
2--1 = 2+ 1 = 3

$d= \sqrt{(-5)^2+(3)^2$

Solve the exponents.

(-5)²= -5*-5= 25
(3)²= 3*3=9

$d= \sqrt{25+9}$

Add.

$d= \sqrt{34}$

This radical cannot be simplified, so the distance between the two points is <u>√34</u> and <u>choice 3 </u> is correct.

6 0

3 years ago

Read 2 more answers

Match each vector operation with its resultant vector expressed as a linear combination of the unit vectors i and j.

Cloud [144]

Answer:

3u - 2v + w = 69i + 19j.

8u - 6v = 184i + 60j.

7v - 4w = -128i + 62j.

u - 5w = -9i + 37j.

Step-by-step explanation:

Note that there are multiple ways to denote a vector. For example, vector u can be written either in bold typeface "u" or with an arrow above it $\vec{u}$ . This explanation uses both representations.

$\displaystyle \vec{u} = \langle 11, 12\rangle =\left(\begin{array}{c}11 \\12\end{array}\right)$ .

$\displaystyle \vec{v} = \langle -16, 6\rangle= \left(\begin{array}{c}-16 \\6\end{array}\right)$ .

$\displaystyle \vec{w} = \langle 4, -5\rangle=\left(\begin{array}{c}4 \\-5\end{array}\right)$ .

There are two components in each of the three vectors. For example, in vector u, the first component is 11 and the second is 12. When multiplying a vector with a constant, multiply each component by the constant. For example,

$3\;\vec{v} = 3\;\left(\begin{array}{c}11 \\12\end{array}\right) = \left(\begin{array}{c}3\times 11 \\3 \times 12\end{array}\right) = \left(\begin{array}{c}33 \\36\end{array}\right)$ .

So is the case when the constant is negative:

$-2\;\vec{v} = (-2)\; \left(\begin{array}{c}-16 \\6\end{array}\right) =\left(\begin{array}{c}(-2) \times (-16) \\(-2)\times(-6)\end{array}\right) = \left(\begin{array}{c}32 \\12\end{array}\right)$ .

When adding two vectors, add the corresponding components (this phrase comes from Wolfram Mathworld) of each vector. In other words, add the number on the same row to each other. For example, when adding 3u to (-2)v,

$3\;\vec{u} + (-2)\;\vec{v} = \left(\begin{array}{c}33 \\36\end{array}\right) + \left(\begin{array}{c}32 \\12\end{array}\right) = \left(\begin{array}{c}33 + 32 \\36+12\end{array}\right) = \left(\begin{array}{c}65\\48\end{array}\right)$ .

Apply the two rules for the four vector operations.

$\displaystyle \begin{aligned}3\;\vec{u} - 2\;\vec{v} + \vec{w} &= 3\;\left(\begin{array}{c}11 \\12\end{array}\right) + (-2)\;\left(\begin{array}{c}-16 \\6\end{array}\right) + \left(\begin{array}{c}4 \\-5\end{array}\right)\\&= \left(\begin{array}{c}3\times 11 + (-2)\times (-16) + 4\\ 3\times 12 + (-2)\times 6 + (-5) \end{array}\right)\\&=\left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle\end{aligned}$

Rewrite this vector as a linear combination of two unit vectors. The first component 69 will be the coefficient in front of the first unit vector, i. The second component 19 will be the coefficient in front of the second unit vector, j.

$\displaystyle \left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle = 69\;\vec{i} + 19\;\vec{j}$ .

$\displaystyle \begin{aligned}8\;\vec{u} - 6\;\vec{v} &= 8\;\left(\begin{array}{c}11\\12\end{array}\right) + (-6) \;\left(\begin{array}{c}-16\\6\end{array}\right)\\&=\left(\begin{array}{c}88+96\\96 - 36\end{array}\right)\\&= \left(\begin{array}{c}184\\60\end{array}\right)= \langle 184, 60\rangle\\&=184\;\vec{i} + 60\;\vec{j} \end{aligned}$ .

$\displaystyle \begin{aligned}7\;\vec{v} - 4\;\vec{w} &= 7\;\left(\begin{array}{c}-16\\6\end{array}\right) + (-4) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}-112 - 16\\42+20\end{array}\right)\\&= \left(\begin{array}{c}-128\\62\end{array}\right)= \langle -128, 62\rangle\\&=-128\;\vec{i} + 62\;\vec{j} \end{aligned}$ .

$\displaystyle \begin{aligned}\;\vec{u} - 5\;\vec{w} &= \left(\begin{array}{c}11\\12\end{array}\right) + (-5) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}11-20\\12+25\end{array}\right)\\&= \left(\begin{array}{c}-9\\37\end{array}\right)= \langle -9, 37\rangle\\&=-9\;\vec{i} + 37\;\vec{j} \end{aligned}$ .

7 0

3 years ago

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

MA_775_DIABLO [31]

Answer:

m<3 = 97

m<10 = 97

m<9 = 83

m<5 = 97

m<7 = 83

m<16 = 97

Step-by-step explanation:

m<3 = m<2 because of vertical angles

m<10 = m<2 because of corresponding angles

m<9 + 97 = 180

m<9 = 83

m<5 + 83 = 180

m<5 = 97

m<7 = m<6 because of vertical angles

m<16 = m<5 because of alternate exterior angles.

4 0

3 years ago

I WOULD LIKE HELP WITH THIS PLEASE!!!

Ainat [17]

Answer:

the answer would be 80 :)

6 0

3 years ago