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inn [45]
3 years ago
8

What kind of bond is pictured in the diagram to the left? Describe the movement of the valence electrons in the bond above? (Hin

t sharing or giving up?)

Chemistry
1 answer:
poizon [28]3 years ago
6 0

Answer:

into one atom

Explanation:

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I WILL GIVE BRAINLIEST!!!!!
Alexxx [7]
                                    HNO₃ + H₂S → S + NO + H₂<span>O

Assign Oxidation Number:

                                L.H.S                               R.H.S
           N in HNO</span>₃  =  +5                                     +2  =  N in NO
               S in H₂S  =  -2                                       0  =  S in S

Write Half cell Reactions:
Reduction Reaction:
                                 
3e⁻  +   HNO₃   →   NO      -------(1)
Oxidation Reaction:
                                  H₂S   →   S  +  2e⁻             -------(2)

Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons. 

                                          6e⁻  +   2 HNO₃   →   2 NO
                                    
                                             3 H₂S   →   3 S  +  6e⁻
                                                                                  Cancel e⁻s,
                                 ______________________________
                               
                             2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  H₂O

Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.

                            2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  4H₂O


                                
4 0
3 years ago
A single 250 gram
Gala2k [10]

2.2 x 10^-2

0.055 / 250 = 0.00022 - This would be 2.2 x 10^-4, but the question is asking for percent, not proportion, so multiply by 100% to get the percentage.

0.00022 * 100% = 0.022% = 2.2 * 10^-2

6 0
3 years ago
What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:

PH= -㏒[H+]
     = -㏒(4.81x10^-7) = 6.32

3 0
3 years ago
How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
ozzi
The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


since M/v%   is  mass  of solute  in  grams per 100  ml

convert Mg to  g
1 g = 1000 mg  what  about  1.5 mg =?  grams
=   1.5 /1000 = 0.0015 grams


volume is therefore =  100 (  mass/ M/v%)

= 100  x(  0.0015/ 0.4) =  0.375  ML
6 0
3 years ago
1. the mass of one electron is
kupik [55]

Answer:

Mass of one electron is 9.1 × 10⁻³¹ kg

Mass of one proton is 1.673 × 10⁻²⁷ Kg

Mass of one neutron is 1.675 × 10⁻²⁷ Kg

 

<u>-TheUnknownScientist</u><u> 72</u>

4 0
2 years ago
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