Answer:
35.8 g
Explanation:
Step 1: Given data
Mass of water: 63.5 g
Step 2: Calculate how many grams of KCl can be dissolved in 63.5. g of water at 80 °C
Solubility is the maximum amount of solute that can be dissolved in 100 g of solute at a specified temperature. The solubility of KCl at 80 °C is 56.3 g%g, that is, we can dissolve up to 56.3 g of KCl in 100 g of water.
63.5 g Water × 56.3 g KCl/100 g Water = 35.8 g KCl
Answer:
C
The answer is C pleaaaaaaase
D. Electron cloud allowed the particles to pass through
Answer: 97.2223 ml
Explanation:
The rule that we will use to solve this problem is:
M2*V1 = M2*V2 where:
M1 is the initial concentration = 3.5 m
V1 is the initial volume = 0.25 l = 250 ml
M2 is the final concentration = 9 m
V2 is the final volume that we need to find
Substitute with the givens in the above equation to get V2 as follows:
3.5*250 = 9*V2
V2 = <em><u>97.2223 ml</u></em>
Electrostatic forces work on anything that is charged.
<span>Usually only protons and electrons, but also some other elementary particles.
</span>d. a proton attracting an electron
