Answer:
HCl conc.= 6.0mol/L
Explanation:
From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,
Answer: water
Explanation:if you look at a globe most of it is blue and blue on a globe is water so that means water covers most of the earth
Looking at the information given above, you will notice that, for cancer disease, the patient was sure that his parents and aunts did not have the disease condition but it does not know whether his grand parents and uncles have it or not. Therefore, he will have to find out more about history of cancer in the family.
For heart disease condition, his parents and uncles have heart problems. Because of this, the patient has to undergo preventative care for heart disease.
For diabetes condition, his grand parents have diabetes and he also thinks that his aunts have. Due to this fact, the patient also have to receive preventative care for diabetes.
Answer:
The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>
Explanation:
Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M
Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M
<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)
The equilibrium constant (
) for the given chemical reaction, is given by the equation:
![K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%20%7B%5BHI%5D%5E%7B2%7D%7D%7B%5BH_%7B2%7D%5D%5C%3A%20%5BI_%7B2%7D%5D%7D)
<u><em>At the original equilibrium state:</em></u>
<u><em>Therefore, at the new equilibrium state:</em></u>
![K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%20%7B%5BHI%5D%5E%7B2%7D%7D%7B%280.95%5C%3A%20M%29%20%5Ctimes%20%280.019%5C%3A%20M%29%7D)
![\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}](https://tex.z-dn.net/?f=%5CRightarrow%20K_%7Bc%7D%20%3D%20713.59%20%3D%20%5Cfrac%20%7B%5BHI%5D%5E%7B2%7D%7D%7B0.01805%7D)
![\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88](https://tex.z-dn.net/?f=%5CRightarrow%20%5BHI%5D%5E%7B2%7D%20%3D%20713.59%20%5Ctimes%200.01805%20%3D%2012.88)
![\Rightarrow [HI] = \sqrt {12.88} = 3.589 M](https://tex.z-dn.net/?f=%5CRightarrow%20%5BHI%5D%20%3D%20%5Csqrt%20%7B12.88%7D%20%3D%203.589%20M)
<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>
