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mina [271]
3 years ago
15

4. Diffuse reflection occurs when parallel light waves strike which surface?

Chemistry
2 answers:
nordsb [41]3 years ago
8 0

Answer:

rough surface

Explanation:

Diffuse reflection occurs when parallel light waves strike a rough surface

Orlov [11]3 years ago
8 0

Answer:

Rippling fountain

Explanation:

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Which is NOT an assumption of matter made by the kinetic molecular theory of gases?
sertanlavr [38]

Answer:

a. the Kinetic energy of particles is determined by their mass and their velocity.

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2 years ago
Special characteristics of metals, like being shiny, are called A Descriptions B Phrases C Qualities D Properties
slega [8]
Answer:
d properties
i took a test on this before
8 0
3 years ago
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A researcher selects three regions X, Y, and Z, and records the types of discharge that enter the regions’ rivers.
elixir [45]

Region Z should be monitored more closely to avoid health issues.

<h3>Why region Z should be monitored?</h3>

Region Z should be monitored more closely to avoid potential health issues because region Z produces waste from chemical plants which are dangerous for our water and environment so we can conclude that Region Z should be monitored more closely in order to avoid health issues.

Learn more about discharge here: brainly.com/question/4918499

3 0
2 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
Allisa [31]

Answer:

The mass of water m_{w} = 39.18 gm

Explanation:

Mass of iron m_{iron} = 32.5 gm

Initial temperature of iron T_{1} = 22.4°c = 295.4 K

Specific heat of iron  C_{iron} = 0.448 \frac{KJ}{kg K}

Mass of water = m_{w}

Specific heat of water  C_{w} = 4.2 \frac{KJ}{kg  K}

Initial temperature of water T_{2} = 336 K  

Final temperature after equilibrium T_{f} = 59.7°c = 332.7 K

When iron rod is submerged into water then

Heat lost by water  = Heat gain by iron rod

m_{w} C_{w} (T_{2} - T_{f} ) =  m_{iron} C_{iron} ( T_{f} - T_{1} )

Put all the values in above formula we get

m_{w} × 4.2 × ( 336 - 332.7 ) = 32.5 × 0.448 × ( 332.7 - 295.4 )

m_{w} = 39.18 gm

Therefore the mass of water m_{w} = 39.18 gm

8 0
3 years ago
The half life of radon-222 is 3.8 days. How Much of a 100g sample is left after 15.2 days
professor190 [17]

Answer:  

6.2 g  

Explanation:  

In a first-order decay, the formula for the amount remaining after <em>n</em> half-lives is  

N = \frac{N_{0}}{2^{n}}  

where  

<em>N</em>₀ and <em>N</em> are the initial and final amounts of the substance  

1. Calculate the <em>number of half-lives</em>.  

If t_{\frac{1}{2}} = \text{3.8 da}  

n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{15.2 da}}{\text{3.8 da}}= \text{4.0}

2. Calculate the <em>final mass</em> of the substance.  

\text{N} = \frac{\text{100 g}}{2^{4.0}} = \frac{\text{100 g}}{16} = \text{6.2 g}

4 0
3 years ago
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