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3 years ago

True or false, The atomic number of an element is a whole number that decreases as you read across each row of

Chemistry

1 answer:

torisob [31]3 years ago

5 0

Answer:

I believe it's false because the atomic number is the number of protons in the nucleus of an atom.

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How many moles of aluminum oxide are produced when 6 moles of oxygen gas react?

siniylev [52]

Answer:

4 moles of aluminum and 6 moles of oxygen are produced

4 0

3 years ago

When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and allowed to come to equilibr

Amanda [17]

Answer: The value of $K_c$ for the given reaction is 1.435

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of $N_2O_4$ = 9.2 g

Molar mass of $N_2O_4$ = 92 g/mol

Volume of solution = 0.50 L

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{9.2g}{92g/mol\times 0.50L}\\\\\text{Molarity of solution}=0.20M$

For the given chemical equation:

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial: 0.20

At eqllm: 0.20-x 2x

We are given:

Equilibrium concentration of $N_2O_4$ = 0.057

Evaluating the value of 'x'

$\Rightarrow (0.20-x)=0.057\\\\\Rightarrow x=0.143$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$[NO_2]_{eq}=2x=(2\times 0.143)=0.286M$

$[N_2O_4]_{eq}=0.057M$

Putting values in above expression, we get:

$K_c=\frac{(0.286)^2}{0.143}\\\\K_c=1.435$

Hence, the value of $K_c$ for the given reaction is 1.435

6 0

3 years ago

HELP!!! DUE TONIGHT!!

IRINA_888 [86]

Answer:

K I will attempt

Explanation:

$O_2_{(g)}+ 2H_2_{(g)} => 2H_2O_{(l)}\\$

1 : 2 : 2 (I don't know if this is what the question wants but it is what I would answer)

Hydrogen because it requires 2 moles of H2 to react with 1 mole of O2

24 moles of water. Look at stoichiometric coefficient. 2:2 means 24 moles you get 24 moles

Oxygen. 2 < 5/2. Remember, 1 mole of O2 requires 2 moles of H2. But 5/2 is still greater than 2

First, let's find out how many moles of water we can get. Since O2 is the limiting reactant, and O2:H2O ratio is 1:2, we will get 4 moles of H2O. Then, we can multiply 4 by Avogadro's number which is $6.022*10^{23}$ to get the number of molecules. We get: 2.41 * 10^24 molecules of water.