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nignag [31]
3 years ago
3

A student builds the apparatus shown above. A light string is attached to an object of unknown mass and passed through a tube su

ch that the other end of the string is attached to a second object of mass M M . By holding on to the tube, the student swings the object of unknown mass in a horizontal circle of radius r r while the object of mass M M hanging from the string remains at a constant height. In each trial, the radius r r of the circular path is changed and the tangential speed ν ν of the object of unknown mass is calculated. How can the student determine the value of the unknown mass by using the radius of its circular path and its speed?

Physics
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

One End Of A Light String Is Attached To An Object Of Mass Mo, And The Other End Of The String Is Passed Through A Tube And Attached To A Second Object Of Mass M. The Student Holds On To The Tube And Swings The Object Of Mass Me In A Horizontal Circle While The Object Of Mass M Remains At A Constant Height.

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dimaraw [331]
This question could be solved with this formula:
F . ΔT
From which F= The amount of force applied
and ΔT = the impact time ins seconds

So, the Value of impulse would be:
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= 0.26 Newton Seconds
7 0
3 years ago
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Complete this sentence. If the mass of object A is __________ than object B, then the weight of object A will be _______________
AfilCa [17]

Answer:

Complete this sentence. If the mass of object A is greater than object B, then the weight of object A will be heavier the weight of object B.

Explanation:

If the mass of Object A is more/greater than object B then it would be "heavier"

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The geese fly 23 m/s to the south when they migrate for the winter. Identify if this example is speed or velocity.
kari74 [83]

Answer:

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7 0
3 years ago
a small negatively charged sphere with a mass of 5.4*10^-5 is suspended between two parallel plates. the potential difference is
labwork [276]
Here, Fe = Fg
q.E = m.g
We have: E = 360 V
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g = 9.8 m/s²   [ constant value for earth system ]

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q (360) = 5.4 × 10⁻⁵ × 9.8
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Hope this helps!
3 0
4 years ago
If a second particle, with the same electric charge but ten times as massive, enters the field with the same velocity v ⃗ , what
masya89 [10]

Answer:

Explanation:

When an moving electric charge passes through a uniform magnetic field

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force on the moving charge created by magnetic field

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Centripetal force required for circular motion

= m v² / R

For balancing

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v = B q R / m

Time period of rotation

T = 2π R / v

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For first particle

T₁ =  2 π  m₁ / B q₁

For second  particle

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Putting the values in second equation

T₂ =  2 π  10 m₁ / B q₁

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Given T₁ = T

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3 0
3 years ago
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