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grin007 [14]
3 years ago
15

What happens in this circuit if one of the light bulbs is unscrewed?

Physics
2 answers:
Marizza181 [45]3 years ago
8 0

yes it is B on usa test prep

vichka [17]3 years ago
7 0

Answer:

B. The other bulb stays lit.

Explanation:

You did not provide the picture of the circuit but here are some suggestions.

Based on the choices given:

A)The other bulb goes out.

B)The other bulb stays lit.

C)Current stops flowing in the circuit.

D)The current path in the circuit is broken.

Choices A, C, and D all happen when a light bulb is unscrewed in a series circuit. A series circuit is a circuit where all the resistors are lined up in a single path. In order for current to flow, the resistors need to be all functional. When you take one out, the flow of current stops because the one path it flows through is broken. As a result, other resistors in the circuit will no longer work.

As for choice B, this occurs in a parallel circuit. In a parallel circuit the resistors are arranged in parallel paths. The paths branch off and thus so does the flow of current. If you take out one of the light bulbs in a parallel circuit, the other light bulbss would remain lit because the flow of current has an alternative path to move through.

Attached is a diagram of a series and a parallel circuit.

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marshall27 [118]
<h2><u>Answer:</u></h2>

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All incredible, in the long run — in around 5 billion years — our sun will, as well. When its supply of hydrogen is depleted, the last, sensational phases of its life will unfurl, as our host star extends to wind up a red goliath and afterward shreds its body to consolidate into a white smaller person

7 0
4 years ago
Help please
Naddik [55]

Answer:

acid and bases

Explanation:

4 0
3 years ago
Calculate the speed of a gamma ray with a frequency of 3.0 x 10^19 Hz and a wavelength of 1.0 x 10^-11 m.
Ulleksa [173]

Answer:

Speed of gamma rays = 3 x 10⁸ m/s

Explanation:

Given:

Frequency of gamma ray = 3 x 10¹⁹ Hz

Wavelength of gamma rays = 1 x 10⁻¹¹ meter

Find:

Speed of gamma rays

Computation:

Velocity = Frequency x wavelength

Speed of gamma rays = Frequency of gamma ray x Wavelength of gamma rays

Speed of gamma rays = [3 x 10¹⁹][1 x 10⁻¹¹]

Speed of gamma rays = 3 x [10¹⁹⁻¹¹]

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Speed of gamma rays = 3 x 10⁸ m/s

6 0
3 years ago
PLEASE ANSWER, I NEED HELP
Scorpion4ik [409]

1) The gravitational force between Ellen and the moon is 1.56\cdot 10^{-3} N

2) The two forces are equal, while the acceleration of the bus is smaller than the acceleration of the bicycle.

Explanation:

1)

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

In this problem, we have:

m_1 = 47 kg is the mass of Ellen

m_2 = 7.35\cdot 10^{22} kg is the mass of the moon

r=3.84\cdot 10^8 m is the distance between Ellen and the moon

Substituting, we find the gravitational force between Ellen and the moon:

F=(6.67\cdot 10^{-11})\frac{(47)(7.35\cdot 10^{22})}{(3.84\cdot 10^8)^2}=1.56\cdot 10^{-3} N

2)

We can analyze the forces acting in the collision between the bus and the bicycle by using Newton's third law of motion, which states that:

"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"

Applied to our problem, this means that the force exerted by the bus on the bicycle during the collision (action force) is equal (and opposite) to the force exerted by the bicycle on the bus (reaction force).

Now let's analyze the accelerations of the two vehicles. We can find the acceleration of each vehicle by using Newton's second law:

a=\frac{F}{m}

where

a is the acceleration

F is the force exerted on the vehicle

m is the mass of the vehicle

As we said previously, the force F exerted on each of the two vehicles: so, the acceleration only depends on the mass. In particular, the acceleration is inversely proportional to the mass: therefore, the larger the mass of the vehicle, the smaller the acceleration. This means that the acceleration of the bus is smaller than the acceleration of the bicycle.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

And about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

6 0
3 years ago
A car starts from rest and accelerates uniformly at a rate of 2.0 meter per second squared for 4.0 seconds. During this time int
vagabundo [1.1K]

Answer:

16

Explanation:

\frac{1}{2}  \times 2 \times  {4}^{2}  = 16

7 0
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