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Anna35 [415]
3 years ago
10

we had to drive 150 miles to the hotel we left at 1 p.m. and got there at 4 p.m. what is our average speed

Physics
2 answers:
kirza4 [7]3 years ago
7 0

Answer:

<em>Our average speed was 50 mph</em>

Explanation:

<u>Constant Speed Motion</u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

The distance we had to drive is d=150 miles. If we left at 1 p.m. and got to the hotel at 4 p.m. This means we took t=3 hours to get there.

The average speed is:

\displaystyle v=\frac{150\ miles}{3\ h}

v=50\ mi/h

Our average speed was 50 mph

marta [7]3 years ago
4 0
The answer is 50mi/hr
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3 years ago
A ball is projected with an initial velocity of 40 meter per second and reached maximum height of 160 meters calculate tge angle
Andru [333]

There's a problem with the question as given. Even with a maximum projection angle of <em>θ</em> = 90°, the initial velocity is not large enough to get the ball up in the air 160 m. With angle 90°, the ball's height <em>y</em> at time <em>t</em> would be

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Set <em>y</em> = 160 m, and you'll find that there is no (real) solution for<em> t</em>, so the ball never attains the given maximum height.

From another perspective: recall that

<em>v </em>² - <em>v</em>₀² = 2<em>a </em>∆<em>y</em>

where

• <em>v</em>₀ = initial velocity

• <em>v</em> = final velocity

• <em>a</em> = acceleration

• ∆<em>y</em> = displacement

At its maximum height, the ball has zero vertical velocity, and ∆<em>y</em> = maximum height = 160 m. The ball is in free fall once it's launched, so <em>a</em> = -<em>g</em>.

So we have

0² - (40 m/s)² = -2<em>g </em>(160 m)

but this reduces to

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3 years ago
I need some help with my home work !!!
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A thin walled spherical shell is rolling on a surface. What
ExtremeBDS [4]

Answer:

=\frac{1/3}{5/6} = 0.4

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fraction of rotaional to total K.E

=\frac{1/3}{5/6} = 0.4

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