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Andre45 [30]
3 years ago
15

In this example we see how thermal expansion can actually throw off the accuracy of a length-measuring device—namely, a tape mea

sure. A surveyor uses a steel measuring tape that is exactly 50.000 mm long at a temperature of 20 ∘C∘C. What is its length on a hot summer day when the temperature is 35 ∘C∘C?

Physics
2 answers:
Ulleksa [173]3 years ago
5 0

Answer:

The new length is 50.00885m

Explanation:

linear thermal expansion coefficient Fe 11.8e-6 /K

The new length can be determined using the following equation:

∆L/L = α∆T, where α is linear thermal expansion coefficient

∆L = Lα∆T = 50(11.8e-6)(35-20) = 0.00885 m

New length = ( 50.000 + 0.00885)m =

New length = 50.00885 m

GenaCL600 [577]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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Answer:

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3 years ago
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Look at the diagram below. From the frame of reference of the person riding
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2 years ago
A mountaintop is a height y above the level ground. A woman measures the angle of elevation of the mountaintop to be θ when she
valentina_108 [34]
Let t = Theta and p = Phi
Tan t = y/x    Then x =y/Tant.
Tant = y/(x-d)  x-d = y/Tanp
y/Tant  - d = y/Tanp
y -d*Tanr = y*Tant/Tanp
y-y*Tant/Tanp  =  d*Tanr
y(1 - Tanr/Tanp = d*Tant

y = d*Tant/(1-Tant/Tanp)
7 0
3 years ago
A 795-loop square armature coil with a side of 10. 5 cm rotates at 70. 0 rev/s in a uniform magnetic field of strength 0. 45 t.
Agata [3.3K]

The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.

No. of loop = 795

Diameter of the coil = 10.5 cm

Radius of the coil = 5.25 cm

Magnetic Field, B = 0.45 T

Time, t = 70.0 rev/s

              V_{rms} =\frac{NwAB}{\sqrt{2} }

Where,

              N = No. of loop

              A = Area of the coil

              B = Magnetic Field

              V_{rms} = Voltage rms

Area of the coil = πr²

                        = 86.57 cm²

w = 2π/t

   =( 2 × 3.141)/70.0

   = 0.089

V_{rms} =\frac{795*0.089*86.57* 0.45}{\sqrt{2} }\\\\V_{rms} =\frac{2756.36}{\sqrt{2} }\\\\\\V_{rms} =\frac{2756.36}{1.414 }\\\\V_{rms} = 1.94 * 10^-^5 V

Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

Learn more about rms voltage here:

brainly.com/question/13156072

#SPJ4

8 0
8 months ago
Help me besties ok thx
Pachacha [2.7K]

Answer:

1 \\ 0.5 \times 500 \times 20 \times 20 \\  \ 2 \\ 0.5 \times 0.6 \times 100 \times 100 \\ 3 \\ 1000 \times 0.5 \times 10 \times 10 \\ 1000 \times 0.5 \times 20 \times 20 \\ 1000 \times 0.5 \times 30 \times 30 \\ 4 \\ 0.5 \times 40000 \times 30 \times 30 \\ 5 \\  \sqrt{ \frac{2}{0.1 \times 0.5} }

7 0
2 years ago
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