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soldi70 [24.7K]
3 years ago
7

Using Hooke's law, Fspring=kΔx, find the elastic constant of a spring that stretches 2 cm. when a 4 Newton force is applied to i

t.
A) 1/2N/cm

B) 2N/cm

C) 4N/cm

D) 8N/cm
Physics
1 answer:
liraira [26]3 years ago
3 0

The correct answer is 2 N/cm, I take k12 and that was the correct answer

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What is the momentum of a 200 kg truck travelling at 20 m/s?
geniusboy [140]

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

p=200\times 20\\\\p=4000\ kg-m/s

So, the momentum of the truck is equal to 4000 kg-m/s.

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3 years ago
Most street lights are made from one or two elements mercury or sodium. Explain why astronomers preferred that cities you sodium
lora16 [44]
Mercury is very harmful to the average human being. the mercury can easily be released from the lamp if the lamp is knocked over and broken. mercury is also harmful if inhaled. sodium on the other hand is not harmful in any way.
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3 years ago
A 80-kg person sits on a 2.7kg chair. Each leg of the chair makes contact with the floor on a circle that is 1.3 cm in diameter.
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6 0
3 years ago
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Estimate the number of times the earth will rotate on its axis during a human’s lifetime
Fudgin [204]

Here we have to calculate  the number of rotations made by earth around its own axis in the entire life time of a human being.

The average human life is 50 years .

Each year is 365.5 days

Hence 50 years =50 *365.5 days

                 =18,275 days

The earth rotates around its own axis in 23 hours 56 minutes and 4 second which is approximately equal to 24 hours or one days.

Hence one rotation takes one days.

⇒18,275 days =18,275 rotations

Hence the total number of rotations made by earth around its own axis in the life time of a average human life time will be 18,275 times

7 0
3 years ago
You want to lean your dad's ladder on a smooth wall. If the mass of ladder is 4.42 kg and coefficient
iren [92.7K]

Answer:

angle minimum   θ = 41.3º

Explanation:

For this exercise let's use Newton's second law in the condition of static equilibrium

    N - W = 0

    N = W

The rotational equilibrium condition, where we place the axis of rotation on the wall

We assume that counterclockwise rotations are positive

     fr (l sin θ) - N (l cos θ) + W (l/2 cos θ) = 0

     

the friction force formula is

     fr = μ N

     fr = μ W

we substitute

      μ m g l sin θ - m g l cos θ + mg l /2   cos θ = 0

      μ sin θ - cos θ + ½ cos θ= 0

         

       μ sin θ - ½ cos θ = 0

       sin θ / cos θ = 1/2 μ

       tan θ = 1/2 μ

       θ = tan⁻¹ (1 / 2μ)

       θ = tan⁻¹ (1 (2 0.57))

      θ = 41.3º

7 0
3 years ago
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